Answer:
127.12 m/s
Explanation:
From the question,
Kinetic energy of the bowling ball = Kinetic energy of the ping pong ball
1/2mv² = 1/2m'v'²
Where m = mass of the bowling ball, v = velocity of the bowling ball, m' = mass of the ping pong ball v' = velocity of the ping pong ball
make v' the subject of the equation
v' = √(mv²/m')................ Equation 2
Given: m = 7.0 kg, v = 2.45 m/s, m' = 2.60 g = 0.0026 kg
Subtitute into equation 2
v' = √[(7×2.45²)/0.0026]
v' = √16160.57
v' = 127.12 m/s
Answer:
<u>As</u><u> </u><u>we</u><u> </u><u>kno</u><u>w</u><u> </u><u>that</u><u>,</u><u> </u>
- 1 mm/min = 1.66667E-5 m/s
- 1 m/s = 60000 mm/min
<u>Now</u><u>,</u><u> </u><u>come</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>question</u><u> </u><u>-</u><u> </u>
Result : 2536 mm/min = 0.0422666667 m/s.
When an earthquake strikes usually seismic waves carry the energy outward (a.) With the greatest power at the focus and as the seismic waves travel outward they become more and more weak until they disappear.<span />
Answer:
Kinematics is a <em>subfield of physics, developed in classical mechanics, that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the forces that cause them to move.</em>
Explanation:
Hope this helps!
Blazetoxic123
Answer:
6 rad/s
Explanation:
In a spring the angular frequency is calculated as follows:
where is the angular frequency, is the mass of the object in this case , and is the constant of the spring.
To calculate the angular frequency, first we need to find the constant which is calculated as follows:
Where is the force: , and is the distance from the equilibrium position: .
Thus the spring constant:
And now we do have everything necessary to calculate the angular frequency:
the angular frequency of the oscillation is 6 rad/s