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Sladkaya [172]
3 years ago
7

Consider the nuclear equation below.

Chemistry
2 answers:
anygoal [31]3 years ago
7 0
It’s “c. +1” because the Sodium is losing a proton, which has a positive chage
ahrayia [7]3 years ago
3 0

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

The equation for the given chemical reaction is:

_{11}^{22}\textrm{Na}\rightarrow _{10}^{22}\textrm{Ne}+_{?}^{0}\beta

To know the missing term on the product side, total atomic number and mass number remains the same on both the sides.

Equating the terms of atomic number from both the sides, we get:

11=10+x\\x=+1

This decay is called as positron decay in which a proton gets converted to neutron and an electron neutrino and thus releases positron particles. This particle carries a charge of +1 units.

Hence, the correct answer is Option c.

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The molarity of concentrated acetic acid is 17.45 M. When acetic acid is diluted in water it is commonly called vinegar with a m
Sladkaya [172]

M1 = 17.45 M

M2 = 0.83 M

V2 = 250 ml

M1. V1= M2. V2

V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml

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2 years ago
Elements may be individual atoms or they may form molecules. Compounds can only have which form? PLEASE ANSWER FAST WILL GIVE BR
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All compounds are molecules

I got you! i hope i helped

Explanation:

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3 years ago
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The various atomic masses of the same element are called<u> isotopes</u>. They have the same number of protons but different number of neutrons.
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Don't take my word for it but I think it is
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Given the chemical reaction: Hg2+(aq) + Cu(s) + Hg(s) + Cu2+(aq)
Pavel [41]

Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V

Explanation:

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.

The standard emf of a cell is related to Gibbs free energy by following relation:

\Delta G=-nFE^0

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\Delta G=-2.303RTlog K

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5 0
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