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Sladkaya [172]
3 years ago
7

Consider the nuclear equation below.

Chemistry
2 answers:
anygoal [31]3 years ago
7 0
It’s “c. +1” because the Sodium is losing a proton, which has a positive chage
ahrayia [7]3 years ago
3 0

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

The equation for the given chemical reaction is:

_{11}^{22}\textrm{Na}\rightarrow _{10}^{22}\textrm{Ne}+_{?}^{0}\beta

To know the missing term on the product side, total atomic number and mass number remains the same on both the sides.

Equating the terms of atomic number from both the sides, we get:

11=10+x\\x=+1

This decay is called as positron decay in which a proton gets converted to neutron and an electron neutrino and thus releases positron particles. This particle carries a charge of +1 units.

Hence, the correct answer is Option c.

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What is meant by the limiting reactant why is it necessary to identify the limiting reactant when you want to know what?
WARRIOR [948]

You have the reactants who react to make your products.

Reactants --------> Products

The limiting reactant is the reactant that will RUN OUT FIRST and that will establish the maximum amount of product that will be produced.

To make an example, let's look at this equation and at the following question:

2Al + 6HCl → 2AlCl3 + 3H2

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?

We know that 2Al + 6HCL are the reactants, right?

These 2 reactants will react to create an amount of a certain product in this case they're asking us for the amount of H2 that will be produced. Therefore, we need to find the REACTANT it can be either AL OR HCL.

But, how do we know which one is the limiting reactant?

To know which one is the limiting reactant we need to know HOW MUCH H2 can Al produce, and also how much H2 can HCL produce. Why?

It's simple, because if you find the one that produces the less amount of H2, you know immediately that's the maximum amount of that product that will be produced.

Let's say you have a sandwich that needs to be made with 2 slices of bread, 3 meats and 1 cheese.

But you have got 4 slices of bread, 9 slices of meat, and 5 slices of cheese.

Well, you could make 2 sandwiches with 4 slices of bread, 3 sandwiches with those 9 slices of meat and 5 sandwiches with the 5 slices of cheese.

But, in reality, you can only make 2 sandwiches because you don't have any more bread to produce more sandwiches. You get it? That is the point of limiting reactants, to find what is the actual amount that can be produced.

Coming back to our equation, we can find the number of moles of H2 produced by each one of the reactants, Al and HCl. I'll find the number of moles quickly to show you what the concept of limiting reactant is.

6.0mol Al x 3 mol H2/2 mol Al = 9 mol H2

13 mol HCL x 3 mol H2/6 mol HCL = 6.5 mol H2

As you can see, 6.5 mol of H2 is the maximum that can be produced by the HCL and is less than the Al, so that maximum amount that you will get in the product H2 is no more than 6.5.

4 0
3 years ago
Question 1<br>Amines have what type of functional group?<br>OH<br>O C=0<br>o H-C=0<br>-NH3<br>COOH​
Vlada [557]

Answer:

-NH3

Explanation:

amines are nitrogen containing compounds

5 0
3 years ago
Does an acid gain or lose a hydrogen cation, H+, during an acid-base reaction?
elena-s [515]

It loses an H+.

The bronsted lowry definition for an acid is that an acid is a H+ donor, or giver. So, during an acid based reaction, an acid would lose a H+.

Lose an H+.

6 0
3 years ago
What is the setup to which you compare all the others in an experiment?
ANTONII [103]

Answer:

A part of the experiment that is not being tested and is used for comparison of the experimental results. A control group should be used when conducting an experiment. This group receives the same attention as the test groups, however, it will not be influenced by the variable the other groups are testing.

Explanation:

도움이 되기를 바랍니다.... 안전을 유지하세요 ✨

8 0
2 years ago
15. A 15.30 g sample of calcium (Ca) combines with 7.96 g of sulfur(S) to form calcium sulfide
BlackZzzverrR [31]

Answer:

17.689g

Explanation:

1: First, write out the equation you will follow:

Ca + S ⇒ CaS

2: Use the formula Mass = Mr x moles to work out the moles of both Ca and S - this will enable you to find the limiting reactant.

3: Moles Ca:

Moles = mass/ Mr = 15.3/ 40.1 = 0.382 moles.

4: Moles S:

Moles = mass/ Mr = 7.96/ 32.1 = 0.245 moles.

5: We now know S is the limiting reactant, and as there is a 1:1 ratio between S and CaS, there will also be 0.245 moles CaS.

6: Mass CaS:

Mass = Mr x moles = 72.2 x 0.245 = 17.689g

6 0
3 years ago
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