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guapka [62]
3 years ago
10

Find out how the position of the Sun would be different at 12:00 midday in December than in June. What path would the sun take f

rom sunrise to sunset?
Physics
1 answer:
Ratling [72]3 years ago
6 0

Answer:

Explanation: The Sun is directly overhead at solar noon at the Equator on the equinoxes, at the Tropic of Cancer (latitude 23°26′11.2″ N) on the June solstice and at the Tropic of Capricorn (23°26′11.2″ S) on the December solstice.

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Which of the following BEST describes what occurs in a fusion reaction?
Greeley [361]

Answer:

Two mass nuclei are joined to form one nucleus

Explanation:

As the name implies "fusion", it is the joining of lighter nucleus to form a heavier nucleus to produce energy

4 0
3 years ago
Given a graph of volocity v . Time what does a horizontal line represent
kifflom [539]

Answer:

Acceleration

Explanation:

For example, if the acceleration is zero, then the velocity-time graph is a horizontal line (i.e., the slope is zero). If the acceleration is positive, then the line is an upward sloping line (i.e., the slope is positive).

6 0
3 years ago
he nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particle
12345 [234]

Answer:

A) F = 21.134 N

B) a = 3180.76 × 10^(24) m/s²

Explanation:

A) We are given;

Mass of alpha particle; m = 4.0026 u

Now, 1u = 1.66 × 10^(-27) kg

Thus; m = 4.0026 × 1.66 × 10^(-27)

Distance apart; r = 6.60 × 10^(−15) m

Charge on the alpha particle is;

q = 2e = 2 × 1.6 × 10^(-19) C

Formula for the force between the two alpha particles is;

F = kq1.q2/r²

k = 8.99 × 10^(9) N.m²/C²

q1 = q2 = 2 × 1.6 × 10^(-19) C

F = 8.99 × 10^(9) × (2 × 1.6 × 10^(-19))²/(6.60 × 10^(−15))²

F = 21.134 N

B) acceleration is given by;

a = F/m

Thus; a = 21.134/(4.0026 × 1.66 × 10^(-27))

a = 3180.76 × 10^(24) m/s²

6 0
3 years ago
A boat’s initial velocity is 30m/s. After 2.5 seconds, its velocity is 5m/s
baherus [9]

Answer: -10 m/s

Explanation:

8 0
3 years ago
A sound wave has a frequency of 776 Hz in air and a wavelength of 0.52 m. What is the temperature of the air? Relate the speed o
OLEGan [10]

Answer:

142.7650889

Explanation:

I think the answer above is correct. So to find the velocity of the wave you can do: frequency*wavelength = velocity

in your case, the velocity is equal to 403.5m/s

so we know that the 403.52 is the total velocity of the wave

and the equation: velocity at 0 degrees Celsius * \sqrt{{T}/{273}} where T represents temperature in Kelvins = veloctity

so we set 403.52 = 327*\sqrt{{T}/{273}} and solve for T

T will then equal the degree in Kelvins

so to convert from Kelvins to degrees celsius you subtract 273 from the Kelvins value and you are left with the degrees in Celsius which equals 142.7650889 degrees Celsius

5 0
3 years ago
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