Answer:
Explanation:
Using the principle of moment, assuming the rod is uniform rod of mass 1 kg
the center of mass of the rod will be at 1 m
assuming the system is in equilibrium,
clockwise moment = anticlockwise moment
let the distance of the man shoulder be x from the center of gravity and also is the pivot point
total mass of bucket + mass of honey = 2kg + 3 kg = 5 kg for rear bucket and
2kg + 5 kg = 7 kg for front bucket
( 5kg × ( 1+x)) + ( 1 kg × x) = 7 kg × ( 1 - x)
5 + 5 x + x = 7 - 7x
5 + 6x = 7 - 7x
6x + 7x = 7 - 5
13x = 2
x = 2 / 13 = 0.154 m
the honeybucket man's shoulder is 0.154 m from the center of the pole ( forward ).
Answer:
s is distance so it's dimensions become L.
Nd other side we have ut+1\2at^2.
as 1\2 is a constant it will have dimensions and apply the dimensions to other quantities.
on solving u will get L there also i,e ur LHS = RHS.
thus the equation is dimensionally consistent.
Explanation:
Answer:
14.36m/s
Explanation:
From the law of conservation of linear momentum
m1u1 + m2u2 = v(m1 + m2)
68×17 + 76×12= v(68+76)
1156+912 = 144v
2068 = 144v
v = 2068/144
=14.36 m/s
(d) Acceleration is a vector quantity
