Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
-- If the field were inclined to the surface, then it would have
some component parallel to the surface.
-- Then, since we're talking about a conductor, the charges
on the object would move in response to that component
of the field, until there was no longer any component of the
field trying to move them.
M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h = 0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW
<h3>
Answer:</h3>
189.07 kPa
<h3>
Explanation:</h3>
Concept tested: Boyle's law
<u>We are given;</u>
- Initial volume of the syringe, V1 is 16 cm³
- Initial pressure of the syringe, P1 is 1.03 atm
- New volume of the syringe, V2 is 8.83 cm³
We are required to calculate the new pressure of the syringe;
- We are going to use the concept on Boyle's law of gases.
- According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.
- At varying pressure and volume, k(constant) = PV and P1V1=P2V2
Therefore, to get the new pressure, P2, we rearrange the formula;
P2 = P1V1 ÷ V2
= ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³
= 1.866 atm.
- Thus, the new pressure is 1.866 atm
- But, we need to convert pressure to Kpa
- Conversion factor is 101.325 kPa/atm
Thus;
Pressure = 1.866 atm × 101.325 kPa/atm
= 189.07 kPa
Hence, the new pressure of the air in the syringe is 189.07 kPa
The helium atom is found to contain more particles than the hydrogen atom.
<h3>What is a subparticle?</h3>
An atom is composed of particles and these particles are electrons protons and neutrons. The collective name for these particles is the subatomic particles.
Now we know that the helium atom contains more sub atomic particles than the atom of hydrogen. This is because, the helium atom contains two neutrons and two protons as well as two electrons. On the other hand, the hydrogen atom contains one neutron and one proton as well as one electron.
Thus, the helium atom is found to contain more particles than the hydrogen atom.
Learn more about helium atom:brainly.com/question/4945478
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