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Elis [28]
3 years ago
10

three small balls each of mass 13.3g are suspended separately from a common point by silk threads, each 1.17m long. The balls ar

e identically charged hang at the corners of equilateral triangle 15.3 cm on a side. Find the charge on each ball
Physics
1 answer:
RideAnS [48]3 years ago
8 0
The balls are identical charges hang at the corners of equlilateral
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Which are two characteristics of a proton
Scilla [17]
Positive electric charge and found inside the nucleus
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2 years ago
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Concerning the work done by a conservative force, which of the following statements, if any, are true? It can always be expresse
Vera_Pavlovna [14]

Answer:

It is independent of the path of the body and depends only on the starting and ending points.

Explanation:

In Physics we define a conservative force as a force that is independent of the path of the body and depends only on the starting and ending points.

For conservative forces we can write;

KEi + PEi = KEf +PEf

where;

KEi= initial kinetic energy

PEi= initial potential energy

KEf= final kinetic energy

PEf= final potential energy

This equation is known as the principle conservation of mechanical energy . It applies only to conservative forces where friction is negligible. The term KE + PE  is also known as the total mechanical energy of the system.

3 0
3 years ago
A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob
andre [41]

Answer:

I = -2.1 kg.m/s

Explanation:

Given,

mass of the object,m = 0.30 Kg

initial speed, v_i = 3 m/s

time of collision = 0.20 s

final speed, v_f = -4 m/s

Impulse = change in momentum

I = m (v_f-v_i)

I = 0.30\times (-4-3)

I = -2.1 kg.m/s

Hence, impulse of the object is equal to I = -2.1 kg.m/s

5 0
3 years ago
PLEASE HELP
siniylev [52]
A person standing on the moon watching the earth rotate
3 0
3 years ago
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A spool whose inner core has a radius of 1.00 cm and whose end caps have a radius of 1.50 cm has a string tightly wound around t
White raven [17]

Answer:

v₁ = 37.5 cm / s

Explanation:

For this exercise we can use that angular and linear velocity are related

        v = w r

in the case of the spool the angular velocity for the whole system is constant,

They indicate the linear velocity v₀ = 25.0 cm / s for a radius of r₀ = 1.00 cm,

         w = v₀ /r₀

for the outside of the spool r₁ = 1.5 cm

         w = v₁ / r₁1

since the angular velocity is the same we set the two expressions equal

        \frac{v_o}{r_o} = \frac{v_1}{r_1}

        v1 = \frac{r_1}{r_o} \ \ v_o

let's calculate

       v₁ = \frac{1.50}{1.00} \ \ 25.0

       v₁ = 37.5 cm / s

4 0
3 years ago
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