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Elis [28]
3 years ago
10

three small balls each of mass 13.3g are suspended separately from a common point by silk threads, each 1.17m long. The balls ar

e identically charged hang at the corners of equilateral triangle 15.3 cm on a side. Find the charge on each ball
Physics
1 answer:
RideAnS [48]3 years ago
8 0
The balls are identical charges hang at the corners of equlilateral
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Round your answers to one decimal place.this parallel circuit has two resistors at 15 and 40 ohms. what is the total resistance?
lubasha [3.4K]
1) The equivalent resistance of two resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}
so in our problem we have
\frac{1}{R_{eq}} =  \frac{1}{15 \Omega}+ \frac{1}{40 \Omega}=0.092 \Omega^{-1}
and the equivalent resistance is
R_{eq} =  \frac{1}{0.092 \Omega^{-1}}=10.9 \Omega

2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
I= \frac{V}{R_{eq}}= \frac{12 V}{10.9 \Omega}=1.1 A
4 0
3 years ago
Read 2 more answers
You have two square metal plates with side lengths of (6.50 C) cm. You want to make a parallel-plate capacitor that will hold a
gtnhenbr [62]

Answer:

The necessary separation between  the two parallel plates is 0.104 mm

Explanation:

Given;

length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}

Where;

d is the separation or distance between the two parallel plates;

d = \frac{VL^2 \epsilon_o}{Q} \\\\d =  \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm

Therefore, the necessary separation between  the two parallel plates is 0.104 mm

6 0
3 years ago
The acceleration due to gravity vector is always in the ____ direction.
finlep [7]
It goes in the downward direction
4 0
2 years ago
When the rocket launched the astronauts aboard experienced an acceleration of 32 m/s^2. If one of the astronauts had a mass of 6
sergij07 [2.7K]

Answer:

The question is somewhat vague in that acceleration is not exactly defined:

Usually a = (v2 - v1) / t    which would imply that

a = 32 / g = 32 / 9.8 = 3.27   the acceleration due to change in speed of the rocket

One can also say that the astronaut experiences an acceleration of 9.8 m/s^2 just by being motionless on the surface of the earth.

Then a = (32 - 9.8) / 9.8 = 2.27 due to the acceleration of the rocket

If we assume the first condition then

F = 65 kg * 3.27 * 9.8 m/s^2 = 2083 N

7 0
2 years ago
HELP ! ILL MARK BRAINLIEST HELP ASAP
irina [24]

Answer:

A

Explanation:

In 5 minutes, they went 10 miles at both 2, 3, and 4 checkpoints. The bus then starts to speed up.

Hope this helps!

8 0
3 years ago
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