1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xxMikexx [17]
3 years ago
12

Which step is usually NOT performed when finding a pulse?

Physics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

Answer is B. counting the number of heartbeats for 6 seconds. :)

Explanation:

To quote the text, <em>"You must make a fist with one hand before using the index and middle fingers of your other hand to press down on the artery to find it. Once you have found the artery, locate your pulse and count how many heartbeats you can feel for 10 seconds. Multiply the number by 6 to get the approximate number of heartbeats in 60 seconds, or bpm."</em>

NNADVOKAT [17]3 years ago
4 0
The laST ONE I THINK
You might be interested in
A 10.0-cm-long uniformly charged plastic rod is sealed inside a plastic bag. The net electric flux through the bag is 7.50 × 10
Rina8888 [55]

Answer:

66.375 x 10⁻⁶ C/m

Explanation:

Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as ;

∅ = Q / ε₀        -----------------(i)

Where;

∅ = 7.5 x 10⁵ Nm²/C

ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²

Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;

7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)

Solve for Q;

Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²

Q = 66.375 x 10⁻⁷ C

Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e

L = Q / l     ----------------------(ii)

Where;

Q = 66.375 x 10⁻⁷ C

l = length of the rod = 10.0cm = 0.1m

Substitute these values into equation (ii) as follows;

L = 66.375 x 10⁻⁷C / 0.1m

L = 66.375 x 10⁻⁶ C/m

Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.

3 0
3 years ago
If frequency is kept constant, how are the velocity and wavelength of a wave related?
Elan Coil [88]
<h3><u>Answer;</u></h3>

Velocity and wavelength are directly proportional when frequency is kept constant.

<h3><u>Explanation;</u></h3>
  • <em><u>Frequency of a wave is the number of complete oscillations made by a given wave in one second. </u></em>
  • <em><u>Wavelength on the other hand, is the distance between two successful crests or troughs in a transverse wave or two successful rarefactions or compressions in a longitudinal waves.</u></em>
  • <em><u>The speed of a wave is given by the product of the frequency of a wave and the wavelength.</u></em>
  • <em><u>Speed = Frequency × wavelength, </u></em>
  • <em><u>Therefore, if frequency is kept constant, then the speed of a wave is directly proportional to the wavelength, such that an increase in wavelength increases the speed of the wave and vice versa.</u></em>
3 0
3 years ago
Read 2 more answers
Design a solution that can monitor and minimize the melting of sea ice caused by human activity
dedylja [7]

Answer:

CO2 emissions from fossil fuel burning should be minimized at all cost. The CO2 are gotten when the carbons from hydrocarbons react with air(oxygen). This gas erodes the ozone layer which makes the melting of ice caps faster due to increased amount of heat radiations on the earth. This is the only best and permanent solution to the reduction of the amount of heat rays on the earth which is a global problem.

Objects which reflects back the sunrays could also be inserted into the sea to prevent the melting of the ice caps.

7 0
3 years ago
Is it true muscle mass affects someones flexibility
guapka [62]
It is very very true
8 0
4 years ago
You have a set of calipers that can measure thicknesses of a few inches with an uncertainty of ± 0.005 inches. You measure the t
Bond [772]

Answer:

a) x = (0.0114 ± 0.0001) in , b) the number of decks is 5

Explanation:

a) The thickness of the deck of cards (d) is measured and the thickness of a card (x) is calculated

        x = d / 52

        x = 0.590 / 52

        x = 0.011346 in

Let's look for uncertainty

       Δx = dx /dd Δd

       Δx = 1/52 Δd

       Δx = 1/52  0.005

       Δx = 0.0001 in

The result of the calculation is

        x = (0.0114 ± 0.0001) in

b) You want to reduce the error to Δx = 0.00002, the number of cards to be measured is

           #_cards = n 52

The formula for thickness is

           x = d / n 52

Uncertainty

          Δx = 1 / n 52  Δd

         n = 1/52 Δd / Δx

         n = 1/52 0.005 / 0.00002

         n = 4.8

Since the number of decks must be an integer the number of decks is 5

3 0
4 years ago
Other questions:
  • A ball is thrown straight upward and rises to a maximum height of 18.0 m above its launch point. at what height above its launch
    9·1 answer
  • Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. you may want to review ( pages 29
    5·2 answers
  • Name two noble gases
    14·2 answers
  • True or false most elements are solid at room temperature
    14·1 answer
  • Suppose you are playing hockey on a new-age ice surface for which there is no friction between the ice and the hockey puck. You
    5·1 answer
  • A ball is thrown vertically upward with a speed of 25.1 m/s. How high does it rise? The acceleration due to gravity is 9.8 m/s2
    6·1 answer
  • I need this question's answer lo long define rest <br>​
    6·1 answer
  • How does temperature influence the appearance of a star? Give an example in your response.
    10·1 answer
  • Check out my recent unanswered physics questions :):):):)
    14·2 answers
  • You work at a retail store. Recently, paychecks have had errors and there have been many employee complaints. You have been assi
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!