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ValentinkaMS [17]
3 years ago
11

To produce work a gas is expanded adiabatically from 3 MPa and 300oC to 80 kPa in a piston-cylinder device. Which of these two c

hoices –air with an isentropic expansion efficiency of 90% or neon with an isentropic expansion efficiency of 80% – will produce the most work?

Physics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

Explanation:

Check attachment for solution

Given that, .

The initial gas pressure is

P1 = 3 MPa

The initial gas temperature

T1 = 300°C

The final gas pressure is

P2 = 80 KPa

Which are of two choices

1. Air with an isentropic expansion of 90% efficiency

2. Neon with an isentropic expansion of 80% efficiency

We want to know which will produce more work

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5 0
3 years ago
An elevated water tank holds 1 million gallons of water. Determine the force (in lbf) that the tower structure must be able to w
bixtya [17]

Answer:

8,345,925 lb-f

Explanation:

We know pressure P = F/A = ρgh ⇒ F = ρghA = ρgV

F = ρgV where F = force, ρ = density of water = 1000 kg/m³ , g = acceleration due to gravity = 9.8 m/s² and V = 1 × 10⁶ gallons = 1 × 10⁶ gallons × 1m³/264.2 gallons = 3785 m³

So, F = ρgV = 1000 kg/m³ × 9.8 m/s² × 3785 m³ = 37,093,000 N

We now convert Newtons to pound-force.

1 N = 0.225 lb-f

So, F = 37,093,000 N = 37,093,000 N × 0.225 lb-f/1 N = 8,345,925 lb-f

So, the tower must be able to withstand 8,345,925 lb-f

5 0
3 years ago
What do you notice about the way energy is transferred between objects with different masses?
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3 years ago
How high is an object lifted if the total work done on it is 125 J and the force required to lift the object is 25 N? Use the eq
mixas84 [53]
The answer would be C. 5m
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Hope this helps!
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3 years ago
(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.
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Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

BW = F_{c2}-F_{c1}

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

BW = (88-5)kHz

BW = 83kHz

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f_0 = \sqrt{88*5}

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3 years ago
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