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3 years ago

A Roller Derby Exhibition recently came to town. They packed the gym for two

Physics

1 answer:

arlik [135]3 years ago

7 0

Answer:

14.36m/s

Explanation:

From the law of conservation of linear momentum

m1u1 + m2u2 = v(m1 + m2)

68×17 + 76×12= v(68+76)

1156+912 = 144v

2068 = 144v

v = 2068/144

=14.36 m/s

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List some benefits of Cardiovascular exercise:

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What happens to a light ray passing through the center of a lens?

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Theoretically, the light ray will not change direction. The center of a lens is called the optical center. If the ray of light hits the lens even just a little bit off center, the light ray is refracted. Refraction happens when the incident and exit angles of the ray are different. The optical center is guaranteed to not have any difference in angle, which allows the light ray to pass through directly without changing direction.

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1. Faça as transformações:

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$seconds (s) = hours (h) *3,600 ; h = \frac{s}{3,600} \\g = kg * 1,000; kg = \frac{g}{1,000} \\cm = \frac{m}{100};m = cm * 100$

1. a) 0.5 h = 1,800 s

h) 20 cm = 0.2 m

b) 2.0 h = 7,200 s

i) 5.0 kg = 5,000 g

c) 3.5 h = 12,600 s

j) 1.5 kg = 1,500 g

d) 1/4 h = 900 s

k) 450.0 g = 0.45 kg

e) 3.0 m = 300 cm

l) 20.0 g = 0.02 kg

f) 2.5 m = 250 cm

m) 500.0 g = 0.5 kg

g) 0.5 m = 500 mm

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2 years ago

Infer why the doppler effect can or can not occur in all waves.

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Answer:

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2 years ago

You stand on a frictional platform that is rotating at 1.8 rev/s. Your arms are outstretched, and you hold a heavy weight in eac

dusya [7]

Answer:

20.62361 rad/s

489.81804 J

Explanation:

$I_i$ = Initial moment of inertia = 9.3 kgm²

$I_f$ = Final moment of inertia = 5.1 kgm²

$\omega_i$ = Initial angular speed = 1.8 rev/s

$\omega_f$ = Final angular speed

As the angular momentum of the system is conserved

$I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{9.3\times 1.8}{5.1}\\\Rightarrow \omega_f=3.28235\ rev/s=3.28235\times 2\pi=20.62361\ rad/s$

The resulting angular speed of the platform is 20.62361 rad/s

Change in kinetic energy is given by

$\Delta K=\dfrac{1}{2}(I_f\omega_f^2-I_i\omega_i^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(5.1\times (20.62361)^2-9.3\times (1.8\times 2\pi)^2)\\\Rightarrow \Delta K=489.81804\ J$

The change in kinetic energy of the system is 489.81804 J

As the work was done to move the weight in there was an increase in kinetic energy

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2 years ago