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vesna_86 [32]
3 years ago
11

a 25 ml sample of gas is in a syringe at 22C if it was cool down to 0 C what will the volume of the gas become

Chemistry
1 answer:
Tpy6a [65]3 years ago
6 0

Answer: 0.023 liters

Explanation:

Given that,

Original volume of gas (V1) = 25mL

[convert 25mL to liters

If 1000ml = 1L

25ml = 25/1000 = 0.025L]

Original temperature of gas (T1) = 22°C

[Convert 22°C to Kelvin by adding 273

22°C + 273 = 295K]

New volume of gas (V2) = ?

New temperature of gas (T2) = 0°C

[Convert 0°C to Kelvin by adding 273

0°C + 273 = 273K]

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

0.025L/295K = V2/273K

To get the value of V2, cross multiply

0.025L x 273K = 295K x V2

6.825L•K = 295K•V2

Divide both sides by 295K

6.825L•K/295K = 295K•V2/295K

0.023 L = V2

Thus, the new volume of the gas will be 0.023 litres

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Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)

Generally \Delta  H  =  \Delta  U + \Delta N*  RT

Here \Delta  H is the change in enthalpy

\Delta  U is the change in the internal energy

              \Delta N  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is O_2 and  CO_2 and this are both gases so the change would occur in the number of moles

So  

\Delta  H  =  \Delta  U + [16 -23]*  RT

\Delta  H  =  \Delta  U -7RT

The  negative sign in the equation tell us that the enthalpy\Delta_r H would be less than the Internal energy \Delta_r U

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What is the term for an object's strength of motion?
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Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by
alexdok [17]

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

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Tb (solution)=118.1+14.65

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