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meriva
3 years ago
7

HELP PLEASE !!! Name the Salt formed When Nitric acid + Magnesium hydroxide

Chemistry
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

magnesium chloride

Explanation:

Complete step-by-step answer:

The remaining ions combine to produce the salt of neutralisation. The salt is magnesium chloride. The chemical formula for the compound is $MgC{{l}_{2}}$.

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Air at 30.0% relative humidity is cooled isobarically at 1 atm absolute from 75.0°C to 35.0°C. a. Estimate the dew point and the
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Answer:

a. Dew point: 48.7°C. Degrees of superheat 26.3°C

b. 3.33mol/m^3

c. P=3.34atm

Explanation:

a. Based on the psychometric chart of air, the specific volume of air at the given conditions is:

v =\frac{RT}{PM} =\frac{0.082\frac{atm*L}{mol*K}*348.15K}{1atm*28.97g/mol} *\frac{1m^3}{1000L}*\frac{1000g}{1kg}  =0.98544m^3/kg

The dew point at the specific volume and the 30%-humidity has a value of 48.7°C, it means that there are 75°C-48.7°C=26.3°C of superheat.

b. At 75°C the molar fraction of water is 11580Pa/101625Pa=0.114 moles per cubic meter of feed gas are:

\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.114\frac{1atm}{0.082\frac{atm*L}{mol*K}*348.15K} }*\frac{1000L}{1m^3}    \\\frac{n}{V}=4mol/m^3

Once the 35°C are reached, the mole fraction of water is 1688Pa/101325Pa=0.017 and remaining moles per cubic meter of feed gas are:

\frac{n}{V}=y_{H_2O}\frac{P}{RT}=0.017\frac{1atm}{0.082\frac{atm*L}{mol*K}*308.15K} }*\frac{1000L}{1m^3}    \\\frac{n}{V}=0.673mol/m^3

So the condensed moles per cubic meter of feed gas are:

4mol/m^3-0.673mol/m^3=3.33mol/m^3

c. Considering the Raoult's law, one computes the pressure as follows:

P=\frac{P^{sat}_{H_2O}}{y_{H_2O}}

At 75°C and 30%-humidity, the saturation water vapor pressure has a value of 38599Pa, thus:

P=\frac{38599Pa}{0.114}*\frac{1atm}{101325Pa} \\P=3.34atm

Best regards.

6 0
3 years ago
Biologists designed an experiment to test the effect of compost on the development of root crops. They tested several different
mars1129 [50]

Answer:

it is 56

Explanation:

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3 years ago
Does anyone know any top brainly users that are good at chemistry?
Law Incorporation [45]

Answer:

yes

Explanation:

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3 years ago
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Suppose that instead of mixing water at different temperatures, you instead had two beakers of different liquids at the same tem
Troyanec [42]
Answer: Blue liquid density = 45 grams/70 mL Density = .64 g/mL Yellow liquid density = 80 grams/ 65mL Density = 1.23 g/mL After the liquids are combined the blue less dense liquid will rise to the top, while the yellow more dense liquid will sinks to the bottom.
6 0
3 years ago
How many grams are in 3.01 x 1024 molecules of H2SO4
tresset_1 [31]

Answer:

490. g H₂SO₄

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

3.01 × 10²⁴ molecules H₂SO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

<u>Step 3: Convert</u>

<u />3.01 \cdot 10^{24} \ molecules \ H_2SO_4(\frac{1 \ mol \ H_2SO_4}{6.022 \cdot 10^{23} \ molecules \ H_2SO_4} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} ) = 490.287 g H₂SO₄

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

490.287 g H₂SO₄ ≈ 490. g H₂SO₄

6 0
3 years ago
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