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Vikki [24]
3 years ago
11

put the following in order of a full lunar month: full moon, new moon, 1st quarter, waxing gibbous, waning gibbous, waxing cresc

ent, third quarter, waning crescent
Physics
1 answer:
ASHA 777 [7]3 years ago
4 0

The same cycle of phases repeats over and over and over and over and over again, so I could start the list with whatever phase I want, and build the list until I get to the same phase I  started with.  

But the cultures that track their months by the phases of the Moon (traditional Muslim, traditional Jewish, traditional Chinese) all start the new month with the New Moon, so I guess I'll start my list there too.

-- New Moon

-- Waxing Crescent

-- First Quarter

-- Waxing Gibbous

-- Full Moon

-- Waning Gibbous

-- Third Quarter

-- Waning Crescent

-- next New Moon

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The spectra of most galaxies show redshifts. this means that their spectral lines _________.
spin [16.1K]
Have wavelengths that are longer than normal.
3 0
3 years ago
how fast is a ball going when it hits the ground after being dropped from a height of 16m the acceleration of gravity is 9.8
Aneli [31]

Answer:

17.7 m/s

Explanation:

Given:

y₀ = 0 m

y = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (9.8 m/s²) (16 m − 0 m)

v = 17.7 m/s

The ball is moving at a speed of 17.7 m/s when it hits the ground.

8 0
3 years ago
An elevator is accelerating upward at a rate of 3.6 m/s2. a block of mass 24 kg hangs by a low-mass rope from the ceiling, and a
kozerog [31]
The answer:

<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes

</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have 
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and 
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope

When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²

T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
 and 
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope


5 0
3 years ago
An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's act
seropon [69]
Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector  \hat{i}.
The positive y-axis = the northern direction, with unit vector \hat{j}.

The airplane flies at 340 km/h at 12° east of north. Its velocity vector is
\vec{v}_{1} = 340(sin(15^{o})\hat{i} + cos(15^{o})\hat{j} ) = 88\hat{i} + 328.4\hat{j}

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})

The plane's actual velocity is the vector sum of the two velocities. It is
\vec{v}=\vec{v}_{1}+\vec{v}_{2} = 121.1615\hat{i}+306.0473\hat{j}

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h

The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°

Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.
8 0
3 years ago
A classroom that normally contains 40 people is to be airconditioned with window air-conditioning units of 5-kW cooling capacity
oksano4ka [1.4K]

Answer:

About  2 units.

Explanation:

We assume that there is no heat dissipating instrument in the room

Total cooling load of the room is defined from the given below equation

Q_{cooling}=Q_{light}+Q_{people}+Q_{heat gain}

where

Q_{light}= 10*100 W =1 KW

Q_{people} = 40*360 KJ/h= 4 KW

Q_{heat gain}=15000KJ/h= 4.17 KW

Q_{cooling}= 1+4+4.17=9.17 KW

the number of air conditioner unit is =\frac{9.17}{5}=1.83

 which is approximately 2 units

   

7 0
3 years ago
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