Can someone help me with this please?

Order least to greatest 0.5,3/16,0.75,5/48

katovenus [111]

Answer:5/48,3/16,0.5,0.75

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!

GREYUIT [131]

Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠ $BFG= \frac{1}{2}(arcBEG-arcBG)$ . We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have $2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]$ . Doing all the simplifying inside there we have $2x+146= \frac{1}{2}(122-4x-4x-238)$ and $2x+146= \frac{1}{2}(-8x-116)$ . Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.

3 0

3 years ago

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

3 years ago

Find the area of the kite. 13 12 8 主 A= lin²

rewona [7]

Answer:

100㏑²

Step-by-step explanation;

first of all you find the base using the pythagoras theorem

that is, √13² - 12² =√25 = 5

so 5 is the base of the right angle in the big isoceles triangle

so the base of the isoceles triangle is 10 [5 + 5]

so for the first triangle the area is 60㏑²

the second triangle is 40㏑²

therefore 60 + 40 = 100㏑²

8 0

3 years ago

What is 2 and 5/8 shown as a decimal

slavikrds [6]

The answer to your question is 2.625

5 0

3 years ago

Read 2 more answers