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Neko [114]
3 years ago
13

A balloon contains 5.5 L of air at 303 K and 101.3 kPa. After an hour, the air inside the balloon cools to 297 K. What is the fi

nal volume of the air in the balloon, assuming that it is an ideal gas and that the pressure does not change?
Chemistry
2 answers:
blagie [28]3 years ago
7 0
The final volume of the air in the balloon would be about 5.4 L
Mkey [24]3 years ago
4 0

Answer:

Final Volume = 5.39L

Explanation:

Parameters given:

Initial Volume (V1) = 5.5L

Initial Temperature (T1) = 303K

Initial Pressure = 101.3 kPa

Final Temperature (T2) = 297K

Final Volume (V2) = ?

Pressure is constant

The formular relating these parameters is Charles law. Charles's Law states that the Volume (V) of a gas is directly proportional to the temperature (T). This law is valid as long as the pressure and the amount of gas remains constant.

V1 / T1 = V2 / T2

making V2 subject of interest,

V2 = (T2 * V1) / T1

V2 = (297 * 5.5 ) / 303

V2 = 5.39L

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If the chemist mistakenly makes 250 mL of solution instead of the 200 mL, what molar concentration of sodium nitrate will the ch
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Answer:

0.120M is the concentration of the solution

Explanation:

<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>

<em />

Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.

To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:

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<h3>0.120M is the concentration of the solution</h3>
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