Answer:
2.445 g
Explanation:
Step 1: Given and required data
- Energy in the form of heat required to boil the water (Q): 5525 J
- Latent heat of vaporization of water (∆H°vap): 2260 J/g
Step 2: Calculate the mass of water
We will use the following expression.
Q = ∆H°vap × m
m = Q / ∆H°vap
m = 5525 J / (2260 J/g)
m = 2.445 g
Answer: Heat of vaporization is 41094 Joules
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 429 K = 760 torr
= final pressure at 415 K = 515 torr
= enthalpy of vaporisation = ?
R = gas constant = 8.314 J/mole.K
= initial temperature = 429 K
= final temperature = 515 K
Now put all the given values in this formula, we get
![\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B515%7D%7B760%7D%3D%5Cfrac%7B%5CDelta%20H%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B429K%7D-%5Cfrac%7B1%7D%7B415K%7D%5D)
Thus the heat of vaporization is 41094 Joules
Answer:
Ion-dipole forces
Explanation:
Na⁺ is a cation, that is, an ion with a positive charge.
NH₃ has polar covalent bonds (due to the difference in electronegativity between nitrogen and hydrogen). According to the VESPR theory, it has a trigonal pyramidal shape with a lone pair. As a consequence, it has a net dipole moment and the molecule is polar.
The intermolecular forces between Na⁺ (ion) and NH₃ (dipole) are ion-dipole forces.
Answer:
hope its help you
Explanation:
2.600 × 10^-5 × 6.100 × 10^-5 = 1.586 × 10-9
4.7 M It may be wrong, but I hope it helps!
Explanation:
When you're diluting a solution, you're essentially keeping the number of moles of solute constant while changing the total volume of the solution.
Now, let's assume that you don't know the equation for dilution calculations.
In this case, you can use the molarity and volume of the concentrated solution to determine how many moles of hydrochloric acid you start with.
c
=
n
V
⇒
n
=
c
⋅
V
n
HCl
=
18 M
⋅
190
⋅
10
−
3
L
=
3.42 moles HCl
You then add water to get the total volume of the solution from
190 mL
to
730 mL
.
The number of moles of hydrochloric acid remains unchanged, which means that the molarity of the diluted solution will be
c
=
3.42 moles
730
⋅
10
−
3
L
=
4.7 M
