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Greeley [361]
4 years ago
5

Is the flame test a test for the cation (metal listed first) or the anion (nonmetal listed second)?

Chemistry
1 answer:
RoseWind [281]4 years ago
7 0

Answer:

the answer is metal  hope it helps

Explanation:

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If a tube is 2.2 meters in length, how long is the the tube in feet ?​
trapecia [35]

Answer:

7.22 feet long

Explanation:

1 meter = 3.28084 feet

2.2 × 3.28084 = 7.2<u>1</u>785

= 7.22

I hope this is helpful :)

3 0
3 years ago
Where are the protons and neutrons and electrons located in an atom?
Rus_ich [418]
The protons and neutrons are located in the nucleus of an atom, while the electrons are located in the orbital cloud. <span />
8 0
3 years ago
Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.
BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
  • Reading the Periodic Table
  • Writing Compounds
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

<u>Step 3: Use Dimensional Analysis</u>

<u />6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} ) = 511.901 g NO₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

511.901 g NO₂ ≈ 510 g NO₂

6 0
3 years ago
The picture below shows the positions of the Earth, Moon, and Sun during an eclipse.
SVETLANKA909090 [29]

Answer:

it is option c liner eclipse

7 0
3 years ago
Read 2 more answers
Noble gas configuration
saw5 [17]

Answer:

Rubidium= [Kr] 5s^1

Calcium= [Ar] 4s^2

Aluminium= [Ne] 3s^2 3p^1

Explanation:

A noble gas configuration begins with the elemental symbol of the last noble gas prior to the atom. The symbol is then followed by the remaining electrons.

Hope this helped! good luck :)

3 0
3 years ago
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