All categories

3 years ago

Which of the following is an important difference between climate and weather?

Chemistry

1 answer:

ANEK [815]3 years ago

5 0

Explanation:

Weather can be defined as the day-to-day changes in the atmospheric parameters like temperatures, humidity, rainfall, and pressure. When these weather changes are observed for approximately over 30 years, the climate of the regions can be determined by understanding the patterns.

You might be interested in

If 9.8g water is used in electrolysis, what is the percent yield if 5.6g of oxygen was

ANEK [815]

Answer:

Approximately $64\%$ .

Explanation:

$\displaystyle \text{Percentage Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\%$

The actual yield of $\rm O_2$ was given. The theoretical yield needs to be calculated from the quantity of the reactant.

Balance the equation for the hydrolysis of water:

$\rm 2\, H_2O \, (l) \to 2\, H_2\, (g) + O_2\, (g)$ .

Note the ratio between the coefficient of $\rm H_2O\, (g)$ and $\rm O_2\, (g)$ :

$\displaystyle \frac{n(\mathrm{O_2\, (g)})}{n(\mathrm{H_2O\, (aq)})} = \frac{1}{2}$ .

This ratio will be useful for finding the theoretical yield of $\rm O_2\, (g)$ .

Look up the relative atomic mass of hydrogen and oxygen on a modern periodic table.

$\rm H$ : $1.008$ .
$\rm O$ : $15.999$ .

Calculate the formula mass of $\rm H_2O$ and $\rm O_2$ :

$M(\mathrm{H_2O}) =2\times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}$ .

$M(\mathrm{O_2}) =2\times 15.999 = 31.998\; \rm g \cdot mol^{-1}$ .

Calculate the number of moles of molecules in $9.8\; \rm g$ of $\rm H_2O$ :

$\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{9.8\; \rm g}{18.015\; \rm g \cdot mol^{-1}} \approx 0.543991\;\rm g \cdot mol^{-1}$ .

Make use of the ratio $\displaystyle \frac{n(\mathrm{O_2\, (g)})}{n(\mathrm{H_2O\, (aq)})} = \frac{1}{2}$ to find the theoretical yield of $\rm O_2$ (in terms of number of moles of molecules.)

$\begin{aligned} n(\mathrm{O_2}) &= \displaystyle \frac{n(\mathrm{O_2\, (g)})}{n(\mathrm{H_2O\, (aq)})} \cdot n(\mathrm{H_2O}) \\ &\approx \frac{1}{2} \times 0.543991\; \rm mol \approx 0.271996\; \rm mol \end{aligned}$ .

Calculate the mass of that approximately $0.271996\; \rm mol$ of $\rm O_2$ (theoretical yield.)

$\begin{aligned}m(\mathrm{O_2}) &= n(\mathrm{O_2}) \cdot M(\mathrm{O_2}) \\ &\approx 0.271996\; \rm mol \times 31.998\; \rm g \cdot mol^{-1} \approx 8.70331 \; \rm g \end{aligned}$ .

That would correspond to the theoretical yield of $\rm O_2$ (in term of the mass of the product.)

Given that the actual yield is $5.6\; \rm g$ , calculate the percentage yield:

$\begin{aligned}\text{Percentage Yield} &= \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\% \\ &\approx \frac{5.6\; \rm g}{8.70331\; \rm g} \times 100\% \approx 64\%\end{aligned}$ .

4 0

2 years ago

In a galvanic cell, electrons are transferred from one half cell to the other as the redox reaction progresses.

tia_tia [17]

the two process that occur in a cell are

oxidation: this is loss of electron by electrode. the metal electrode loaes electrons and get oxidized and forms ions

the ions get migrated to solution

Reduction: here the ions present in solution gains electron and get deposited on electrodes.

so gain of electrons is by ions

electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.

5 0

2 years ago

Read 2 more answers

In terms of electrons, what is the difference between a covalent and ionic bond

kramer

Answer:

An ionic bond essentially donates an electron to the other atom participating in the bond, while electrons in a covalent bond are shared equally between the atoms. Ionic bonds form between a metal and a nonmetal. Covalent bonds form between two nonmetals

7 0

2 years ago

5.2 G of HCl are dissolved in 25 mL of solution. What is the molarity?

Kobotan [32]

Answer:

0.21 M

Explanation:

Molarity is the calculation of the solution in which the number of solute per liter of the solutions. It is the most common measurement unit that is used to measure the concentration of the solution.

The molarity is the unit that is used to measure or calculate the volume of the solvent. The amount of solvent is used in the chemical reaction.

The amount of the two solvent in the same quantity is measured by the formula called c1v1 and c2v2.

6 0

3 years ago

LOOK AT THE IMAGE ABOVE PLEASE SOMEONE HELP OMG PLEASE IM LITERALLY STRESSED PLEASE HELP. I got the answer wrong. Please help an

Anna35 [415]

D, the more liquid there is, the less the temperature will be affected

8 0

3 years ago