Answer:
Final Temperature = 28.2 oC
Explanation:
Information given;
Mass of Iron = 20.8g
Initial Temperature of Iron = 100C
Mass of water = 55.3g
Initial temperature of water = 25.3 C
The presence of a coffee cup calorimeter hints that there is no heat loss to the surrounding and that the iron and water are at thermal equilibrium.
Thermal equilibrium means that there is no heat transfer going on between the bodies, which simply means that the bodies are at the same temperature.
Hence, both bodies would the same final temperature (T2)
H = M * C * ΔT (For iron)
H = 20.8 * 0.449 * ( 100 - T2)
H = 9.3392 ( 100 - T2)
H = 933.92 - 9.3392T2
H = M * C * ΔT (For water)
H = 55.3 * 4.184 * (T2 - 25.3)
H = 231.3752 (T2 - 25.3)
H = 231.3752T2 - 5853.79
Since they are in thermal equilibrium it means H (Iron) = H (water).
This leads to;
933.92 - 9.3392T2 = 231.3752T2 - 5853.79
231.3752T2 + 9.3392T2 = 5853.79 + 933.92
240.7144 T2 = 6787.71
T2 = 28.2 oC
Answer:
39.2 L at STP
Explanation:
Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.
= 39.2 L
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