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snow_tiger [21]
4 years ago
13

How is a coefficient different than a constant... please give me an example as well thank you.. I’m giving max points

Mathematics
2 answers:
Elan Coil [88]4 years ago
7 0

Answer:

A coefficient is a number that is in front of a variable. A number that is multiplied by a variable in a variable expression; in an expression such as 3ab, the numerical coefficient of ab is 3. The word constant means unchanging. Since a number’s value never changes, a number with no variable factors is a constant. A constant is a numerical term in an expression. a term that has no variables

Example: 5a+4  The coefficient is 5 and the constant is 4 because it does not have a variable in front of it.

Hope this helps

KatRina [158]4 years ago
6 0
A coefficient is the number in front of the letter, and a constant is just a number.
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Answer: t-13 C

Step-by-step explanation:

If the regular price of a tent is 13 and Harold has a coupon for 13 off, this means Harold has been subsidized by a factor of 13. The amount Harold will pay will be 13 less than t which is t-13 i.e 13 subtracted from the total regular price.

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Palindrome numbers are numbers that read the same foward or backward. Here are some palindrome numbers: 11, 121, 75257, and 1234
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Answer:

99.

Step-by-step explanation:

A palindrome number is one that can be read in the same way both from the front and from the back. A clear example is the number 242, which starts and ends in the same way from the front or back.

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Therefore, considering the 9 hundreds between 100 and 1000, there will be 90 palindromes, which added to the 9 between 10 and 100 give a total of 99 palindromes.

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Read 2 more answers
The function y = x 2 - 10x + 31 has a ____
katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

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3 years ago
What is the distance from 10 To 0
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Answer:

10

Hope this helps :)

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