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nlexa [21]
3 years ago
7

Write 4 different mixed decimals that equal 11 wholes

Mathematics
1 answer:
Softa [21]3 years ago
5 0
There are an infinite number of answers. One possible answer is 3.5+1.2+2.4+3.9=11. The explanation of how I arrived at this follows: A mixed decimal is a whole number followed by a fractional part so an example would be 3.4 or 2.5. To get 4 different mixed decimals that sum to 11 follow these steps: 1. Start with 11 and subtract any mixed decimal from 11 that is smaller than 11. So I will subtract 3.5    11-3.5=7.52. Take the 7.5 from the last step and subtract another mixed decimal from 7.5 that is smaller than 7.5. I will subtract         1.2    7.5-1.2=6.33. Take the 6.3 and subtract another mixed decimal from 6.3 that is smaller than 6.3. I will subtract 2.4    6.3-2.4=3.94. Now I take all of the numbers that I subtracted and add them together along with the 3.9 that was left over and I get       3.5+1.2+2.4+3.9=11

I hope that this helps you! =D
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1239.3 cm^3

Step-by-step explanation:

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Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options. 0
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I think the answers are...

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
mariarad [96]

Answer:

a) 0.1587 (or 15.87%)

b) 0.0478 (or 4.78%)

c) 0.7935 (or 79.35%)

Step-by-step explanation:

Find the following probabilities:

(a) the thickness is less than 3.0 mm

We need to find the area under the Normal curve with a mean of 4.5 mm and a standard deviation of 1.5 mm to the left of 3 mm

<h3>(See picture 1 attached) </h3>

We can do that with the help of a calculator or a spreadsheet.

<em>In Excel use </em>

<em>NORMDIST(3,4.5,1.5,1) </em>

<em>In OpenOffice Calc use  </em>

<em>NORMDIST(3;4.5;1.5;1) </em>

and we get the value 0.1587 (or 15.87%)

(b) the thickness is more than 7.0 mm

Now we need the area to the right of 7 (1 - the area to the left of 7)

<h3>(See picture 2 attached) </h3>

<em>In Excel use </em>

<em>1-NORMDIST(7,4.5,1.5,1)  </em>

<em>In OpenOffice Calc use  </em>

<em>1-NORMDIST(7;4.5;1.5;1) </em>

and we get the value 0.0478 (or 4.78%)

(c) the thickness is between 3.0 mm and 7.0 mm

We are looking for the area between 3 and 7

<h3>(See Picture 3) </h3>

Since the area under the Normal equals 1, we have

Area to the left of 3 + Area between 3 and 7 + Area to the right of 7 = 1

Hence,  

0.1587 +  Area between 3 and 7 + 0.0478 = 1

and

Area between 3 and 7 = 1 - 0.1587 - 0.0478 = 0.7935 (or 79.35%)

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3 years ago
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