All categories

2 years ago

What is one way to test weather an unknown solution is acidic or basic ?

Chemistry

1 answer:

alisha [4.7K]2 years ago

5 0

Use indicators such as :

Indicator Color in acid Color in alkali

methy lorange red yellow

phenolphthalein colorless pink

You might be interested in

Why is light a wave?

madreJ [45]

Answer:

an electromagnetic wave

Explanation:

6 0

2 years ago

What happens when you decrease the pressure from 150 kPa to 50 kPa on liquid water at 100 ºC?

Tems11 [23]

D. liquid water vaporizes.

I have attached a phase diagram for water. As you can see, if kPa is 50, and the temperature is 100c. it is in the vapor phase.

4 0

2 years ago

What man-made carbohydrate is banned in Canada, China, and the European Union, but is legal in the United States?

seropon [69]

Potassium bromate is a bleaching / elasticity agent which is legally used in breads in the United States. It has been banned in Canada, China, and the EU due to concerns about its potential links to several health issues including: kidney damage, nervous system damage, cancer, thyroid issues and gastrointestinal distress.

5 0

3 years ago

The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of

Mademuasel [1]

Answer:

\large \boxed{\textbf{609 kJ}}

Explanation:

The formula for the heat absorbed is

q = mCΔT

Data:

m = 2.07 kg

T₁ = 23 °C

T₂ = 191 °C

C = 1.75 J·°C⁻¹g⁻¹

Calculations:

1. Convert kilograms to grams

2.07 kg = 2070 g

2. Calculate ΔT

ΔT = T₂ - T₁ = 191 - 23 = 168 °C

3. Calculate q

$q = \text{2070 g} \times 1.75 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 168 \,^{\circ}\text{C} = \text{609 000 J} = \textbf{609 kJ}\\\text{The heat energy required is }\large \boxed{\textbf{609 kJ}}$

4 0

2 years ago

An electron in a hydrogen atom relaxes to the n=4 level, emitting light of 74 THz.

Solnce55 [7]

Delta E = Ef - Ei
E = energy , h = plank constant , v = frequency
h= 6.626 * 10 ^-34 j*s , T = 10 ^ 12 , v = 74 * 10 ^12 Hz , Hz = s^-1

E = ( 6.626 * 10^ -34 j*s) ( 74 * 10 ^ 12 s^ -1 ) = 4.90 * 10 ^ -20 J
Delta E = Ef - Ei
-4.90 * 10 ^ -20 J = -2.18 * 10 ^ -18J ( 1/4 ^2 - 1/x ^2)
0.0225 = 0.0625 - ( 1/x ^ 2)
0.225 - 0.0625 = - 1/ x ^ 2

- 0.0400 = - 1/x ^2 = -1 / - 0.0400 = x^2
25 = x^2
x = 5

6 0

2 years ago