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3 years ago

A 2.5 L container is filled with propane. The ambient temperature is 25°C and the

Chemistry

1 answer:

madam [21]3 years ago

7 0

Answer:

The pressure inside the container will be 3.3 atmospheres

Explanation:

The relationship between the temperature and pressure of a gas occupying a fixed volume is given by Gay-Lussac's law which states that the pressure of a given amount of gas is directly proportional to its temperature on the kelvin scale when the volume is kept constant.

Mathematically, it expressed as: P₁/T₁ = P₂/T₂

where P₁ is initial pressure, T₁ is initial temperature, P₂ is final pressure, T₂ is final temperature.

The above expression shows that the ratio of the pressure and temperature is always constant.

In the given question, the gas in the can attains the temperature of its environment.

P₁ = 3 atm,

T₁ = 25 °C = (273.15 + 25) K = 298.15 K,

P₂ = ?

T₂ = (55 °C = 273.15 + 55) K = 328.15 K

Substituting the values in the equation

3/298.15 = P₂/328.15

P₂ = 3 × 328.15/298.15

P₂ = 3.3 atm

Therefore, the pressure inside the container will be 3.3 atmospheres

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Elina [12.6K]

Answer:

ΔG = 18KJ/mol

Explanation:

Given data:

ΔS = 0.09 Kj/mol.K

ΔH = 27 KJ/mol

Temperature = 100 K

ΔG = ?

Solution:

Formula:

ΔG = ΔH - TΔS

ΔH = enthalpy

ΔS = entropy

by putting values,

ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)

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2 years ago

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4vir4ik [10]

Answer: Fireworks exploding is a chemical change.

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2 years ago

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Effectus [21]

Answer:

The number of atoms in the outermost shell

Explanation:

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4 0

3 years ago

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

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2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

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3 years ago

Why do airbags fill evenly with gases?

Firdavs [7]

Answer:

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basically, the nitrogen fills the bag

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2 years ago

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