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Mnenie [13.5K]
1 year ago
10

A 2.000 g sample of CoCl2.xH2O is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 1.565 g. What

is the value of x?
Chemistry
1 answer:
Mashutka [201]1 year ago
6 0

The value of X is 2

The total amount of sample taken is 2.00 g

The amount of sample left in the oven after drying is 1.565g

The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven

                                 = 2.00 - 1.565

                                = 0.435 grams

The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205

The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415

Therefore the ratio of these two are in 1:2 ratio

The complete chemical reaction is   CoCl2.2H20

To know more about the Similar calculation and explanation click here:

brainly.com/question/14967837

#SPJ4

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Answer:

\large \boxed{\text{460 dg}}

Explanation:

1. Convert decagrams to grams

\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}

2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

3 0
4 years ago
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What hybridization is required for central atoms that have a tetrahedral arrangement of electron pairs? A trigonal planar arrang
Ksivusya [100]

Answer:

The required hybridization for a central atom that have:

a tetrahedral arrangement of electron pairs        is  sp^3

a trigonal planar arrangement of electron pairs   is  sp^2

a linear arrangement of electron pairs                 is   sp

Explanation:

From the given information:

The required hybridization for a central atom that have:

a tetrahedral arrangement of electron pairs        is  sp^3

a trigonal planar arrangement of electron pairs   is  sp^2

a linear arrangement of electron pairs                 is   sp

Hybridization is the mixing and blending of two or more pure atomic orbitals ( s, p and d) to forma two or more hybrid atomic orbitals that are identical in shape and energy e. sp ,sp² , sp³, sp³d hybrid orbitals.

Examples:

Tetrahedral

In CH₄ , carbon C is the central atom.

A 2s electron is excited from the ground state of boron 1s²2s²2p² to one of the empty orbitals to 2p to give the excited state 1s²2s²2p³.

In the excited state of carbon, the 2-s orbital can be mixed with the 2p orbitals in three ways : sp³, sp² and sp hybridization. For the formation of four sp³ hybrid orbitals, the 2s orbital are mixed with all the three p orbitals. The four sp³ hybrid orbitals are tetrahedrally arranged with a bond angle of 109.5⁰

Trigonal Planar

In BF₃ , Boron B is the central atom

A 2s electron is excited from the ground state of boron 1s²2s²2p¹ to one of the empty orbitals to 2p. The 2s orbital is then mixed with two orbitals of 2p to form three sp² hybrid orbitals that are trigonal planar arranged in the plane in order to minimize repulsion. They bonds between them form an equal strength and with bond angles of 120⁰

Linear arrangement:

In BeCl₂, Be is the central atom

To provide the unpaired electrons for covalent bonds a 2s electron is excited to a 2p orbital. Thereafter, the two atomic orbitals hybridize to give two identical orbitals called sp hybrid orbitals. The  sigma bond for,ed are equal in bond lengths and form a bond angle of 180°

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3 years ago
A fossil you are radiometrically dating contains 4 micrograms of Uranium 235 and 4 micrograms of Lead 207. Uranium 235 decays to
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The rate at which radioactive substances disintegrate is a constant for a

given radioactive material.

  • <u>The fossil is 710 million years old</u>.

Reasons:

The half-life of a radioactive material is the time it takes half of the nucleus

of a radioactive material to disintegrate into other forms of materials

through the given off of energy and particles.

The half life of Uranium 235 = 710 million years

The product of the decay of Uranium 235 = Lead 207

The mass of Uranium 235 in the fossil = 4 micrograms

The mass of Lead 207 in the sample = 4 micrograms

Therefore, the mass of Lead 207 in the fossil is equal to the mass of

Uranium 235, therefore, a minimum of half of the Uranium 235 has

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The time of decomposition of the Uranium 235 = 1 Half life = 710 million years

The age of the fossil = The time in which the Uranium has been

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million years

  • <u>The age of the fossil = 710 million years</u>

Using the formula for half-life, we get;

\displaystyle N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

The fossil contains initially only Uranium 235 with a minimum mass of 4 mg

+ 4 mg = 8 mg, which gives;

N₀ = 8 mg

N(t) = The current mass of Uranium 235 = 4 mg

\displaystyle t_{1/2} = 710 million years

\displaystyle 4 = 8 \cdot  \left (\dfrac{1}{2} \right )^{\dfrac{t}{710}

\displaystyle \frac{4}{8}  = \frac{1}{2} = \left (\dfrac{1}{2} \right )^{\dfrac{t}{710}

Therefore;

\displaystyle \left( \frac{1}{2}\right)^1 = \left (\dfrac{1}{2} \right )^{\dfrac{t}{710}

\displaystyle 1 = {\dfrac{t}{710}

t = 710

  • <u>The age of the fossil, </u><u><em>t</em></u><u> = 710 million years</u>

Learn more here:

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