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2 years ago

What is programming language? Describe it's types.

1 answer:

7 0

A programming language is a vocabulary and set of grammatical rules for instructing a computer device to perform specific tasks. the term programming language usually refers to high level languages, such as BASIC, C, C++, COBOL, Java, FORTRAN, Ada, and Pascal! i hope i was able to help :)

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Counting atoms worksheet answer key i need help!!

katovenus [111]

Answer is in a pho $^{}$ to. I can only uplo $^{}$ ad it to a file host $^{}$ ing service. link below!

bit. $^{}$ ly/3a8Nt8n

6 0

3 years ago

Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .

Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg is .284 mole

1.84 g of S is .5739 mole

1.365 g of O is .8531 mole you can see the ratio is ~ 1 :2 :3

Mg S2 O3

4 0

2 years ago

How much 2.0 M phenylmagnesium chloride solution is needed if adding 2.9 mmol of Grignard reagent to a reaction? Your answer sho

Vladimir [108]

Answer:

1,45 mL

Explanation:

The Grignard reaction is a very important organometallic chemical reaction where the Grignard reagent ( alkyl, vinyl, or aryl-magnesium halides) acts as nucleophile in order to the formation of Carbon-Carbon bonds.

In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:

2,9 mmol × $\frac{1mL}{2,0mM}$ = 1,45 mL

I hope it helps!

3 0

2 years ago

What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.

koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

What is the mass (grams) of salt in 10.0 m³ of ocean water?

We have this data:

1.000 mol salt is equal to 58.44 g salt
1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

1 L = 1dm³
1 m³ = 10³ dm³

We can use proportions:

$10.0m^{3} .\frac{10^{3}dm^{3} }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt$

8 0

3 years ago

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Nat2105 [25]

To answer the problem above first we need to find the difference of molar mass of NI3 from I2, 394.71 g/mol - 253.80 g/mol = 140.91 g/mol. Knowing the molar mass of the difference of NI3 from I2, in equation mass (g) / moles (mol) = molar mass, then we substitute. 3.58g / moles = 140.91 g/mol.
moles = 3.58 / 140.91 = 0.025 moles.

6 0

3 years ago

What is programming language? Describe it's types.​

What is programming language? Describe it's types.