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vovikov84 [41]
3 years ago
12

Lithium carbonate, li2co3, contains 18.8 % lithium and is used in the treatment of mental illnesses such as bipolar disorder. wh

at mass of lithium is present in a 1.70−g dose of lithium carbonate?
Chemistry
1 answer:
masha68 [24]3 years ago
5 0
Assuming that the percentage composition is on the basis of weight percentage, therefore the mass of lithium would simply be the product of the two, that is:
mass Lithium = 0.188 * 1.70 g
mass Lithium = 0.3196 g = 0.32 g
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\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

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Molarity is found by dividing the moles of solute by liters of solution.

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We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

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78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

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\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

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\frac {1 \ L }{ 1000 \ mL}

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molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

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molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

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