<u>Given information:</u>
Mass of NaCl (m) = 87.75 g
Volume of solution (V) = 500 ml = 0.5 L
Molar mass of NaCl (M) = 58.44 g/mol
<u>To determine:</u>
The molarity of NaCl solution
<u>Explanation:</u>
Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)
i.e. M = moles of solute/liters of solution = n/V
Moles of solute (n) = mass of solute (m)/molar mass (M)
moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles
Therefore,
Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M
<u>Ans: (D)</u>
<span>plasmas that reach a temperature equal to their surroundings
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Answer:
53.29% of acetic acid is Oxygen
Explanation:
Step 1: Given data
Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.
Step 2: the molar masses
The molecular mass of acetic acid is:
4* H = 4* 1.01 g/mole
2* C = 2*12 g/mole
2*O = 2* 16 g/mole
Total molar mass = 4+ 24+32 = 60.052 g/mole
Step 3: Calculate the mass percent
32 g of the 60.052 g is Oxygen
(32/60.052) *100% = 53.29%
53.29% of acetic acid is Oxygen.
Answer: D
Explanation: Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Tellurium (Te) and, Astatine (At) are all metalloids