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2 years ago

Need help on this question asap pleasee

Chemistry

1 answer:

algol [13]2 years ago

6 0

Answer:

9.0 moles of CaO

Explanation:

We have the reaction equation as follows;

Fe2O3 + Ca3(PO4)2 -------> 2FePO4 + 3CaO

Now we know from the equation that;

1 mole of iron III oxide yields 3 moles of CaO

Therefore;

3 moles of iron III oxide yields 3 * 3/1

= 9.0 moles of CaO

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Calculate the pHpH of a 0.10 MM solution of HClHCl . Express your answer numerically using two decimal places.

alisha [4.7K]

Answer: The pH 0f 0.10 solution of HCl is 1.00

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$HCl\rightarrow H^++Cl^{-}$

According to stoichiometry,

1 mole of $HCl$ gives 1 mole of $H^+$

Thus $0.10$ moles of $HCl$ gives = $\frac{1}{1}\times 0.10=0.10$ moles of $H^+$

Putting in the values:

$pH=-\log[0.10]$

$pH=1.00$

Thus pH 0f 0.10 solution of HCl is 1.00

8 0

3 years ago

What happens to the molecules of a gas when the gas is heated?

sladkih [1.3K]

Answer of this question is D

5 0

2 years ago

Read 2 more answers

Please help asap and thank you

natulia [17]

Answer:

Metamorphic rock

Explanation:

metamorphic rocks do not get hot enough to melt they just get denser if they did they would become igneous rocks.

7 0

3 years ago

Mr. Aguilar has ice on his wrist, literally. If the ice on Mr. Aguilar’s wrist (H2O) weighs 546 grams, how many ice particles ar

Lunna [17]

Answer:

The answer to your question is 1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

= 2 + 16

= 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

18 g ---------------- 6.023 x 10²³ particles

546 g --------------- x

x = (546 x 6.023 x 10²³) / 18

3.- Simplification

x = 3.289 x 10²⁶ / 18

4.- Result

x = 1.83 x 10²⁵ particles

6 0

3 years ago

Mature elephants consume an average of 600 pounds of food per day. If an elephant

MAXImum [283]

Answer:

$\large \boxed{\text{4 600 000 kg or 4600 Mg}}$

Explanation:

1. Calculate the adult life

If the elephant is an adult from its 10th birthday until the day before its 56th birthday, its

Adult life = 55 - 10 + 1 = 46 yr

2. Convert years to days

$\text{Adult life} = \text{46 yr} \times \dfrac{\text{365.25 da}}{\text{1 yr}} = \text{16 800 da}$

3. Convert days to pounds of feed

$\text{Feed} = \text{16 800 da} \times \dfrac{\text{600 lb}}{\text{1 da}} = 1.01 \times 10^{7} \text{ lb}$

4. Convert pounds to kilograms and megagrams

$\text{Feed} =1.01 \times 10^{7} \text{ lb} \times \dfrac{\text{1 kg}}{\text{2.20 lb}} =\textbf{4 600 000 kg} = \textbf{4600 Mg}\\\\\text{The elephant will eat $\large \boxed{\textbf{4 600 000 kg or 4600 Mg}}$ of food.}$

Note: The answer can have only two significant figures because that is all you gave for age of the elephant.

5 0

3 years ago