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3 years ago

Need help on this question asap pleasee

Chemistry

1 answer:

algol [13]3 years ago

6 0

Answer:

9.0 moles of CaO

Explanation:

We have the reaction equation as follows;

Fe2O3 + Ca3(PO4)2 -------> 2FePO4 + 3CaO

Now we know from the equation that;

1 mole of iron III oxide yields 3 moles of CaO

Therefore;

3 moles of iron III oxide yields 3 * 3/1

= 9.0 moles of CaO

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10.0 g of gaseous ammonia and 6.50 g of oxygen gas are introduced into a previously evacuated 5.50 L vessel. If the ammonia and

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Answer:

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Explanation:

The reaction that occurs in the vessel is:

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O₂ is limiting reactant. The excess moles of NH₃ are:

0,587 - 0,163 = 0,424 moles of NH₃

These moles are:

$0,424mol * \frac{17,031g}{1mol} =$ 7,22g of NH₃

Knowing O₂ is limiting reactant, mass of NO and H₂O are:

$0,203molO_{2}*\frac{4molNO}{5molO_{2}}*\frac{30,01g}{1molNO} =$ 4,87g of NO

$0,203molO_{2}*\frac{6molH_{2}O}{5molO_{2}}*\frac{18,02g}{1molH_{2}O} =$ 4,39g of H₂O

The total mass is: 7,22g + 4,87g + 4,39g = 16,48g ≡ 16,5g

-The same mass add in the first. By matter conservation law-

As vessel volume is 5,50L, density is:

16,5g/5,50L = 3g/L

I hope it helps!

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