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3 years ago

How did thomson’s findings revise dalton’s atomic theory??

1 answer:

8 0

Dalton thought that atoms were indivisible particles, and Thomson's discovery of the electron proved the existence of subatomic particles. ... The positive and negative charges cancel producing a neutral atom. images.tutorvista.com. Later discoveries by Rutherford and others lead to additional revisions to atomic theory.

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What does law and theory have common

Ronch [10]

Answer:

It is a misconception that theories turn into laws with enough research.

Hope it helps

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3 years ago

Complete the steps for converting 3.6 gallons per minute to milliliters per second. (1 gallon = 3.79 liters and 1 liter = 1,000

AlekseyPX

Given that,

Capacity = 3.6 gallons per minutes

Convert it into milliliters per seconds

Since, 1 gallon = 3.79 liters

1 liters = 1000 milliliters

Capacity= (3.6*3.79*1000)/(60)

Capacity = 227.4 milliliters per second.

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3 years ago

Pure sodium metal placed in water will spark and ignite, as well as form bubbles and gas. What are the signs that this is a chem

ad-work [718]

<h3><u>Answer;</u></h3>

Heat is produced
Light is produced
Bubbles appear

<h3><u>Explanation;</u></h3>

Chemical reactions involve the chemical interaction of two or more chemical substances, result in a new substance being formed, and are usually irreversible.
The signs of chemical reactions include gas formation, energy release in the form of light or flame, heat absorption, precipitate formation, and color change.

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3 years ago

Read 2 more answers

During which stage of the cell cycle does the cell condense chromosomes and break down the nuclear envelope? Group of answer cho

Natalka [10]

Answer:

Prophase

Explanation:

During the Prophase

6 0

3 years ago

A room with 3.1-m-high ceilings has a metal plate on the floor with V = 0V and a separate metal plate on the ceiling. A 1.1g gla

miss Akunina [59]

Answer:

The ball traveled 0.827 m

Explanation:

Given;

distance between the metal plates of the room, d = 3.1 m

mass of the glass, m = 1.1g

charge on the glass, q = 4.7 nC

speed of the glass ball, v = 4.8 m/s

voltage of the ceiling, V = +3.0 x 10⁶ V

The repulsive force experienced by the ball when shot to the ceiling with positive voltage, can be calculated using Coulomb's law;

F = qV/d

|F| = (4.7 x 10⁻⁹ x 3 x 10⁶) / (3.1)

|F| = 4.548 x 10⁻³ N

F = - 4.548 x 10⁻³ N

The net horizontal force experienced by this ball is;

$F_{net} = F_c - mg\\\\F_{net} = -4.548 *10^{-3} - (1.1*10^{-3} * 9.8)\\\\F_{net} = -15.328*10^{-3} \ N$

The work done between the ends of the plate is equal to product of the magnitude of net force on the ball and the distance traveled by the ball.

$W = F_{net} *h\\\\W = 15.328 *10^{-3} * h$

W = K.E

$15.328*10^{-3} *h = \frac{1}{2}mv^2\\\\ 15.328*10^{-3} *h = \frac{1}{2}(1.1*10^{-3})(4.8)^2\\\\ 15.328*10^{-3} *h =0.0127\\\\h = \frac{0.0127}{15.328*10^{-3}}\\\\ h = 0.827 \ m$

Therefore, the ball traveled 0.827 m

4 0

3 years ago