Answer:
5.51 m/s^2
Explanation:
Initial scale reading = 50 kg
assume the greatest scale reading = 78.09 kg
<u>Determine the maximum acceleration for these elevators</u>
At rest the weight is = 50 kg
Weight ( F ) = mg = 50 * 9.81 = 490.5 N<u>
</u>
<u>
</u>At the 10th floor weight = 78.09 kg
Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N
F = change in weight
Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)
50 * a = 275.61
Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
Water sheds i hope this helps give me a brainiest answer
<span>Use Charles' Law:
v1/T1 = v2/T2
88.2/(273+35) = v2/(273+155)
where v2 is the new volume.
I hope this helps!!!</span>
The anwser is 1.475124 horsepower.
