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LenaWriter [7]
3 years ago
10

A bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 6.20×105m/s2 for 8.10×10

-4s. What is its muzzle velocity (that is, its final velocity)?
Physics
1 answer:
kati45 [8]3 years ago
7 0

Answer:

502.2 m/s

Explanation:

initial velocity, u = 0 m/s

Let the final speed is v.

acceleration, a = 6.2 x 10^5 m/s^2

time taken, t = 8.10 x 10^-4 s

The muzzle speed is the final speed.

Use first equation of motion

v = u + a t

v = 0 + 6.2 x 10^5 x 8.10 x 10^-4

v = 502.2 m/s

Thus, the muzzle speed of the bullet is 502.2 m/s.

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Suppose one organ in the organ system failed to work properly, How would the organ system be affected? Would it still be able to
scoray [572]

The organ system failing would affect the rest of the body. You would probablly not live long. The human anatomy is very important. It won work properly. It will affect the rest of your body and probably land you in the hospital. This is why one failing organ system can be fatal.

8 0
3 years ago
Why are hurricanes considered more damaging than tornadoes when tornadoes have stronger winds
chubhunter [2.5K]

-- A tornado follows a path that's a few miles wide, for a few hours.
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-- A hurricane follows a path that's several hundred miles wide,
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8 0
3 years ago
Read 2 more answers
Two point charges are 10.0cm apart and have charges of 2.0uC and -2.0uC, respectively. What is the magnitude of the electric fie
elena-14-01-66 [18.8K]
The electric field generated by a point charge is given by:
E= k_e \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 Nm^2 C^{-2} is the Coulomb's constant
Q is the charge
r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them. 

Let's calculate first the electric field generated by the positive charge at that point:
E_1=k_e  \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =+7.19 \cdot 10^6 N/C
where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:
E_2=k_e \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(-2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =-7.19 \cdot 10^6 N/C
where the negative sign means its direction is toward the charge.

If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
E_{tot} =E_1 + E_2 = 7.19 \cdot 10^6 N/C+7.19 \cdot 10^6 N/C=1.44 \cdot 10^7 N/C
3 0
3 years ago
5. Tại sao khi lặn ta luôn cảm thấy tức ngực và càng lặn sâu thì cảm giác tức ngực càng tăng? A. Ap suất của nước giảm ​​B. Ap s
natali 33 [55]

Answer:

c and d

Explanation:

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7 0
3 years ago
A 5.0-kg centrifuge takes 95 s to spin up from rest to its final angular speed with constant angular acceleration. A point locat
stellarik [79]

Answer:

(a) 17.37 rad/s^2

(b) 12479

Explanation:

t = 95 s, r = 6 cm = 0.06 m, v = 99 m/s, w0 = 0

w = v / r = 99 / 0.06 = 1650 rad/s

(a) Use first equation of motion for rotational motion

w = w0 + α t

1650 = 0 + α x 95

α = 17.37 rad/s^2

(b) Let θ be the angular displacement

Use third equation of motion for rotational motion

w^2 = w0^2 + 2 α θ

1650^2 = 0 + 2 x 17.37 x θ

θ = 78367.87 rad

number of revolutions, n = θ / 2 π

n = 78367.87 / ( 2 x 3.14)

n = 12478.9 ≈ 12479

4 0
3 years ago
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