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IrinaVladis [17]
3 years ago
7

A race car starts from rest and accelerates down a track at a rate of 3.0 m/s2

Physics
1 answer:
7nadin3 [17]3 years ago
3 0
<h3>Answer:</h3>

30 m/s

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Velocity (u) = 0 m/s

Acceleration of the Car (a) = 3 m/s²

Time Interval (t) = 10 seconds

<u>Speed of the Car After 10 seconds:</u>

From the First equation of motion:

v = u + at

replacing the given values

v = 0 + (3)(10)

v = 30 m/s

Hence, the car is moving at a velocity of 30 m/s after 10 seconds

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which of the following instruments is used to measure air pressure? a. thermometer b. barometer c. anemometer d. hygrometer
Kryger [21]
The correct answer is B. barometer

Thermometer is used to measure temperature, anemometer is used to measure wind speed, while a hygrometer is used to measure humidity.
8 0
3 years ago
Read 2 more answers
There are 120 degrees in a straight angle. true false
mixas84 [53]
That would be false.
Straight angle= 180 degrees
Obtuse angle= Above 90, and lower than 180
Acute angle= Below 90
Hope this helps! (:
6 0
4 years ago
Read 2 more answers
How fast and in what direction must galaxy A be moving 17 an absorption Line found at 500 nm for a stationary galaxy 1s shifted
emmainna [20.7K]

Answer:

v = 0.22 c and wavelength is decrease so galaxy A is move away from stationary galaxy

v = 0.095 c and wavelength is increase so galaxy B come toward stationary galaxy

Explanation:

Given data

found = 500 nm

shifted A = 400 nm

shifted B = 550 nm

to find out

How fast and in what direction is galaxy

solution

we use here formula  that is

(λ) shifted = √(1-β / 1+β)  (λ)found

1-β / 1+β =  (4/5)²         ..................1

1-β / 1+β =  16 / 25

β = 0.22

v/c = 0.22

v = 0.22 c

here wavelength is decrease so galaxy A is move away from stationary galaxy

and

here according to equation 1

and we use shifted 550 nm

so

1-β / 1+β =  (5.5/5)²

1-β / 1+β =  30.25 / 25

β = 0.095

so  v/c = 0.095

v = 0.095 c

here wavelength is increase so galaxy B come toward stationary galaxy

3 0
3 years ago
One-half second after starting from rest, a freely falling object will have a speed of about:_________
snow_tiger [21]

One-half second after starting from rest, a freely falling object will have a speed of about 5 m/s.

<h3>What do you mean by falling object?</h3>

Falling things include goods, tools, garbage, and rubbish that are blown, dropped, or displaced from heights.

Physical science research frequently involves the study of gravity. Of course, what makes things fall is the force of gravity. A force of attraction between two objects is constant. This pulling force is similar to the pull of gravity.

given free fall from rest i.e.

initial velocity u=0 m/s

acceleration  a = 10m/s2

time t=0.5 seconds

we know final velocity v = u + at = 0 + (10 *0.5) = 5m/s

To learn more about the  falling object, visit: brainly.com/question/13299152

#SPJ4

7 0
2 years ago
The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C).1.75 J/(g⋅°C). How much heat energy is needed to raise the t
poizon [28]

Answer:

Heat energy required = 687.96 kJ

Explanation:

Heat energy required, H = mCΔT.

Mass of cooking oil, m = 2.34 kg = 2340 g

Specific heat of cooking oil, C = 1.75 J/(g⋅°C)

Initial temperature = 23 °C

Final temperature = 191 °C

Change in temperature, ΔT = 191 - 23 = 168 °C

Substituting values

            H = mCΔT

            H = 2340 x 1.75 x 168 = 687960 J = 687.96 kJ

Heat energy required = 687.96 kJ

4 0
3 years ago
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