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3 years ago

A race car starts from rest and accelerates down a track at a rate of 3.0 m/s2

Physics

1 answer:

7nadin3 [17]3 years ago

3 0

<h3>Answer:</h3>

30 m/s

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Velocity (u) = 0 m/s

Acceleration of the Car (a) = 3 m/s²

Time Interval (t) = 10 seconds

<u>Speed of the Car After 10 seconds:</u>

From the First equation of motion:

v = u + at

replacing the given values

v = 0 + (3)(10)

v = 30 m/s

Hence, the car is moving at a velocity of 30 m/s after 10 seconds

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A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d

PolarNik [594]

Answer:

a. 600 ml, 12

Explanation:

The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

5 0

4 years ago

5. A man in a car is listening to the radio. The radio station is broadcasting at a frequency of 85 MHz from two radio transmitt

nasty-shy [4]

Answer:

Speed = 0.00392 m/s

Explanation:

Solution:

Frequency of the radio = 85 MHz

If we have the frequency, we can calculate the wavelength of the radio wave.

As we know,

Frequency = speed of light/wavelength

wavelength = c/f

c = speed of light = 3 x $10^{8}$ m/s

So,

Wavelength = 3 x $10^{8}$ m/s / 85 x $10^{6}$ Hz

Wavelength = 3.5294 m

Man gets disturbed reception at t = 15 min

t = 15 x 60 = 900 s

t = 900 s

Speed = distance/time

Here, distance is wavelength. So,

Speed = 3.5294 m / 900 s

Speed = 0.00392 m/s

Hence, the man's car is going with speed of 0.00392 m/s

3 0

3 years ago

A 3.00 × 10^-6 kg ant rides the second hand of an enormous vertical wall clock. The ant smoothly sweeps a circle of radius 50.0

kotykmax [81]

Answer:

1.65×10⁻⁶ N

Explanation:

m = Mass of ant = $3\times 10^{-6}\ kg$

r = Radius = 50 m

t = Time taken to complete on rotation = 60 seconds

Angular velocity

$\omega=\frac{2\pi}{t}\\\Rightarrow \omega=\frac{2\pi}{60}$

Centripetal acceleration is force that is acting outward

$F_c=m\omega^2r\\\Rightarrow F_c=3\times 10^{-6}\times \left(\frac{2\pi}{60}\right)^2\times 50\\\Rightarrow F_c=1.65\times 10^{-6}\ N$

The magnitude of the upward force felt by the ant due to the second hand would be 1.65×10⁻⁶ N

4 0

3 years ago

Which of the following is not a characteristic of the source of rivers and streams?

MrRa [10]

<span>The water is clearer, has higher oxygen levels, and freshwater fish such as trout and heterotrophs can be found. In the middle of the river, the width increases, so do the species of aquatic green plants and algae. Toward the mouth of the river, the water becomes murky from all the sediments that it has picked up upstream.<span>
</span></span>

7 0

4 years ago

An object has a net charge of +5 Coulombs.

exis [7]

The net charge of the electron will be there because there is no exponents there

3 0

3 years ago