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IrinaVladis [17]
3 years ago
7

A race car starts from rest and accelerates down a track at a rate of 3.0 m/s2

Physics
1 answer:
7nadin3 [17]3 years ago
3 0
<h3>Answer:</h3>

30 m/s

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Velocity (u) = 0 m/s

Acceleration of the Car (a) = 3 m/s²

Time Interval (t) = 10 seconds

<u>Speed of the Car After 10 seconds:</u>

From the First equation of motion:

v = u + at

replacing the given values

v = 0 + (3)(10)

v = 30 m/s

Hence, the car is moving at a velocity of 30 m/s after 10 seconds

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Answer:

K.E=29.403125J

Explanation:

From the question we are told that

Mass M=100

Height 50-20=30m

Generally the equation for velocity before impact is is is mathematically given by

v=\sqrt{2gh}

v=\sqrt{2*9.8*30}

v=24.25

Generally the equation for Kinetic Energy is is mathematically given by

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}*100*(24.25)^2\\

K.E=29403.125J

K.E=29.403125J

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Explanation:

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2 years ago
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Colum
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"The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis."


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