(A) P(v) = 0.135v
(B) P(h) = 0.234v
<u>Explanation:</u>
Given-
Mass of the ball, m = 0.27kg
Force, F = 125N
angle of projection, θ = 30°
Let v be the velocity of the ball.
A) vertical component of the momentum of the volleyball
We know,
P(vertical) = mvsinθ
P(V) = 0.27 X v X sin 30°
P(V) = 0.27 X v X 0.5
P(V) = 0.135v
B) horizontal component of the momentum of the volleyball
We know,
P(Horizontal) = mvcosθ
P(h) = 0.27 X v X cos 30°
P(h) = 0.27 X v X 0.866
P(h) = 0.234v
Answer: velocity of the car is 113.33m/s
Explanation:
From Doppler effect,
in the case which the source is moving towards the observer at rest
f2 = v/(v-vs) *f1
where f2 is the final observed frequency
f1 is the initial observed frequency
v = 340m/s (speed of sound in air)
vs = velocity of the source of sound.
rearranging the above equation
f2*(v - vs) = f1* v
vs = (f1* v/f2) - v
but f1 = 80Hz
f2 = 60Hz
v = 340m/s
substituting,
vs = (80 x 340)/60 - 340
vs = 453.33 - 340
vs = 113.33m/s
velocity of the car is 113.33m/s
The electric force acting on the charge is given by the charge multiplied by the electric field intensity:
where in our problem
and
, so the force is
The initial kinetic energy of the particle is zero (because it is at rest), so its final kinetic energy corresponds to the work done by the electric force for a distance of x=4 m:
Answer:
H = start height (v = 0)
h = present height
v = present speed
assuming no friction
total energy = PE + KE
mgH = mgh + .5mv^2
if PE = KE then
mgH = mgh + mgh
h = H/2
potential energy = kinetic energy when object is at half its start height.
Explanation:
Answer:
Distance travel by go-cart = 500 meter
Explanation:
Given:
Speed of go cart = 25 m/s
Time travel = 20 seconds
Find:
Distance travel by go-cart
Computation:
Distance = Speed x time
Distance travel by go-cart = Speed of go cart x Time travel
Distance travel by go-cart = 25 x 20
Distance travel by go-cart = 500 meter
