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Anit [1.1K]
3 years ago
5

A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?

Physics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

15m/s²

Explanation:

Given parameters:

Initial velocity  = 10m/s

Final velocity  = 40m/s

Time taken  = 2s

Unknown:

Average acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time;

 Acceleration  = \frac{Final velocity   -  Initial velocity }{time}  

  Acceleration = \frac{40 - 10}{2}    = 15m/s²

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a ship A , steaming in a direction 030° with a steady 12 km/h, sight a ship B. The velocity of B relative to A is 10km/h in a di
pickupchik [31]

Answer: 11 km/h at 339° compass

Explanation:

A sees B moving south at 0 km/h

A is moving north at 12cos30 = 10.392 km/h

Therefore B must be moving north at 10.392 k/h

A is moving east at 12sin30 = 6 km/h

B appears to be moving west at 10 km/h

Therefore B must be moving west at 10 - 6 = 4 km/h

B is moving v = √(4² + 10.392²) = 11.135... 11 km/h

θ = arctan( -4 / 10.392) = -21.05 = 339°

8 0
3 years ago
A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and a speed of 30 m/s. Ideally (no air r
marusya05 [52]

As we know that here no air resistance while ball is moving in air

So here we will say that

initial total energy = final total energy

KE_i + U_i = KE_f + U_f

here we know that

Ui = U_f = 0 (as it will be on ground at initial and final position)

so we will say

KE_i = KE_f

since mass is always conserved

so we will say that final speed of the ball must be equal to the initial speed of the ball

so we have

v_f = v_i = 30 m/s

6 0
3 years ago
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Imagine that you’re observing a collision. Which action would allow you to determine whether the collision is inelastic?
Thepotemich [5.8K]

The answer is B;) in plato

3 0
3 years ago
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A man weighing 700 N lifts a 50.0 N object 2.0 m high. He uses a lever and with a force of 10.0 N. What is the resistance force
umka21 [38]
For the answer to the question above, asking what is the resistance force if a man weighing 700 N lifts a 50.0 N object 2.0 m high. He uses a lever and with a force of 10.0 N. 
we can use the formula below for calculating lever
<span>thus, Le / Lr = 50 / 10 = 5 </span>

5 0
3 years ago
"Suppose you tie a rock to the end of a 0.96 m long string and spin it in a horizontal circle with a constant angular velocity o
Ber [7]

Answer:

The mass of the rock is  m = 2.46406 \ kg

Explanation:

From the question we are told that

   The length of the string is  l  = 0.96 \ m

    The angular velocity is  w =  20.25 \ rad/s

     The tension on the string is T  = 970 \ N

Generally the centripetal force acting on the rock is mathematically evaluated as

       T = mlw^2

making m the subject of the formula

      m = \frac{T}{w^2 * l}

substituting values

     m = \frac{970}{(20.25^2) * (0.96)}

     m = 2.46406 \ kg

       

8 0
3 years ago
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