Answer: 11 km/h at 339° compass
Explanation:
A sees B moving south at 0 km/h
A is moving north at 12cos30 = 10.392 km/h
Therefore B must be moving north at 10.392 k/h
A is moving east at 12sin30 = 6 km/h
B appears to be moving west at 10 km/h
Therefore B must be moving west at 10 - 6 = 4 km/h
B is moving v = √(4² + 10.392²) = 11.135... 11 km/h
θ = arctan( -4 / 10.392) = -21.05 = 339°
As we know that here no air resistance while ball is moving in air
So here we will say that
initial total energy = final total energy

here we know that
(as it will be on ground at initial and final position)
so we will say

since mass is always conserved
so we will say that final speed of the ball must be equal to the initial speed of the ball
so we have

For the answer to the question above, asking what is the resistance force if a man weighing 700 N lifts a 50.0 N object 2.0 m high. He uses a lever and with a force of 10.0 N.
we can use the formula below for calculating lever
<span>thus, Le / Lr = 50 / 10 = 5 </span>
Answer:
The mass of the rock is 
Explanation:
From the question we are told that
The length of the string is 
The angular velocity is 
The tension on the string is 
Generally the centripetal force acting on the rock is mathematically evaluated as

making m the subject of the formula

substituting values

