Answer:
30.22°.
Explanation:
Given that
height of the bridge ,h= 12 ft
The distance of the lake from bridge ,L= 7 m
Lets take angle = θ
Now by using diagram
We can say that
That is why the angle will be 30.22°.
Answer:
Q = 144612 Joules.
Explanation:
Given the following data;
Mass = 2.6 kg
Initial temperature = -27°C to Kelvin = 273 + (-27) = 246K
Final temperature = 0°C to Kelvin = 273K
Specific heat capacity = 2060 J/kgK.
To find the quantity of heat absorbed;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 273 - 246
dt = 27 K
Substituting the values into the equation, we have;
Q = 144612 Joules.
The answer is D. <span>roughly equal parts sand, clay, and silt.
Sand is important because it provides necessary nutrients for the plants (both mineral and organic). Clay is important because it ensures that the plants are able to get proper oxidation, and Slit is important to ensure that the root of the plants anchored properly to the sand.</span>
-244.59meters
Explanation:
The initial position of the object is located at -244.59meters from the origin.
Displacement is the distance from the start to finish of a body.
Final position of the body is at x=-55.25 meters
Amount of displacement is -189.34meters;
let us represent this by a coordinate system in the negative x - direction;
Origin
Start finish 0m
-a -x
-55.25meters
displacement
-189.34meters
Position -a is about 189.34 in left direction from 55.25; this gives: 55.25 + 189.34 = -244.59m in the left direction
learn more:
Displacement brainly.com/question/5461768
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<h3><u>Answer;</u></h3>
200 N
<h3><u>Solution;</u></h3>
Given ;
Weight = 400 N
Length of the ladder = 10 m
Using the equation;
Torque = d x F, where F is the perpendicular force and d is the distance
Calculating torque about the lower end,
Tweight = Twall
400N(5cos30) = F (10sin30)
F = 200 N
Therefore, the magnitude of force exerted on the peg by the ladder is 200 N
