Question

Help me ti take this

Answer 1

Answer:

$-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C$

Step-by-step explanation:

-The questions asks us to integrate and find the integrals of the given function.

-We are given no limits and therefore we will find a generalized integral with a constant.

-Given the function $\int{-\frac{2}{7}x^3-4x^4-2x} \, dx$.

We can integrate the function as:

$\int{-\frac{2}{7}x^3-4x^4-2x} \, dx\\\\=-\frac{2}{7\times4}x^4-\frac{4}{5}x^5-\frac{2}{2}x^2+C\\\\=-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C$

Hence the integral of the function is $-\frac{1}{14}x^4-\frac{4}{5}x^5-x^2+C$