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Bumek [7]
3 years ago
6

A rocket moves through outer space a 12,000 m/s. At this time, how much time would be required to travel the distance from Earth

to the Moon, which is 380,000 km?
Physics
2 answers:
nexus9112 [7]3 years ago
6 0
12000 m/s = 12 km/s. Now to go 380000 km, it will take some time. How much time is given in the formula 12km/s. You go 12 kilometers every second. So you take \frac{380000km}{12km/s} and that gives you 31,666.666 seconds. 
aev [14]3 years ago
4 0

12,000 m  =  12 km

                     (380,000 km) / (12 km/sec)

                 =  (380,000 / 12)      sec

                 =      31,666-2/3 seconds

                 =      8 hours  47 minutes  46.7 seconds 
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4 0
3 years ago
A lightning rod effectively protects a building by transferring the electrical current to the ____________.
maria [59]
It transfers the electrical current from the point of contact on the lightning rod into the ground.
6 0
3 years ago
A train has a final velocity of 110 km/h. It accelerated for 36 s at 0.50 m/s2 . What was its initial velocity
Tems11 [23]

The initial velocity of the train  is 12.56 m/s.

<h3>Initial velocity</h3>

The initial velocity of the train can be determined by using the first kinematic equation as shown below;

v = u + at

u = v - at

where;

  • v is the final velocity = 110 km/h = 30.56 m/s
  • u is the initial velocity

u = 30.56 - (36 x 0.5)

u = 12.56 m/s

Thus, the initial velocity of the train  is 12.56 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

3 0
3 years ago
A thin film of oil (n = 1.27) is located on smooth, wet pavement. When viewed from a direction perpendicular to the pavement, th
alisha [4.7K]

Answer:

Explanation:

The problem is based on interference in thin films

refractive index of water is more than given oil so there will be phase change of π at upper and lower layer of the film .

a )

for constructive interference , the condition is

2μt = nλ where t is thickness of layer , μ is refractive index , λ is wavelength and n is order of the fringe

Putting the values

2 x 1.27 t = n x 640

2 x 1.27 t =  640 ( for minimum thickness n = 1 )

t = 252 nm .

b )

2 x 1.27 t = m₁  λ₁

for destructive interference

2μt = (2m₂+1)λ₂/2

2 x 1.27 t =(2m₂+1)λ₂/2

m₁ λ₁  = (2m₂+1)λ₂/2

2m₁λ₁  = (2m₂+1)λ₂

2m₁ / (2m₂+1) = λ₂ / λ₁

2m₁ / (2m₂+1) = 548/ 640

2m₁ / (2m₂+1) = .85625

2m₁ = .85625 (2m₂+1)

This is the required relation between m₁ and m₂

6 0
4 years ago
Find the magnitude of the gravitational force a 63.5 kg person would experience while standing on the surface of Earth with a ma
Anastaziya [24]

Answer: 3976N

Explanation:

Using the formula for calculating gravitational force between two masses, we have

F = GMm/r^2

Where G is the gravitational constant

M and m are the masses

r is the distance between the masses

F= 6.673 × 10-¹¹ × 5.98 × 10²⁴ × 63.5/ (6.37 × 10^6)^2

F= 2.533×10^16/6.37×10^12

F= 0.3976×10⁴N

F= 3976N

3 0
3 years ago
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