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Triss [41]
3 years ago
6

9. Kokio dydžo Archimedo jėga veikia 0,5 m² tūrio medinį rastą vandenyje?​

Physics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

i dont knowwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww

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The motion map shows an object’s position and velocity at given times. A long black arrow right labeled x. Above that are 5 gree
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The map be changed <u>by adding vectors that are all the same length and placing them above the current top row of vectors</u>

<h3>Further explanation</h3>

A motion map represents the position, velocity, or acceleration of an object at various time readings

a small point or dot describes the position of the object. the object's velocity / acceleration is represented by an arrow / vector.

In this motion map, The arrows (vectors) are all the same length (same speed) and point in the same direction (direction to the right) for t = 0 (origin) to t = 4s

At t = 5s, the object has slowed down, and at t = 7s and 8s the object stops

At t = 9s-11 s, the object accelerates to the left

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<h3>Learn more</h3>

The initial velocity of the bird before the gust of wind

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#LearnwithBrainly

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For a short time the missile moves along the parabolic path y=(18−2x2) km. If motion along the ground is measured as x=(4t−3) km
muminat

Answer with Explanation:

We are given that

y=(18-2x^2) km

x=(4t-3)km

Differentiate x and y w.r.t t

\frac{dx}{dt}=4

\frac{dy}{dt}=-4x\frac{dx}{dt}

\frac{dy}{dt}=-4x\times 4=-16x=-16(4t-3)

v_x=\frac{dx}{dt}=4

v_y=\frac{dy}{dt}=-16(4t-3)

Substitute t=1

v_x=4

v_y=-16(4-3)=-16

Magnitude of velocity=\mid v\mid=\sqrt{v^2_x+v^2_y}

\mid v\mid=\sqrt{4^2+(-16)^2}=16.49 m/s

Hence, the magnitude of the missile's velocity=16.49 m/s

a_x=\frac{d(\frac{dx}{dt})}{dt}=\frac{d(4)}{dt}=0

a_y=\frac{d(\frac{dy}{dt})}{dt}=\frac{d(-16(4t-3))}{dt}=-64

Substitute t=1

a_x=0,a_y=-64

\mid a\mid=\sqrt{a^2_x+a^2_y}

\mid a\mid=\sqrt{0+(-64)^2}=64m/s^2

Hence, the magnitude of acceleration when t=1 s=64m/s^2

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