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Veronika [31]
3 years ago
14

The technology in solar panels allows us to convert the _______ energy from the sun to ________ energy which can be used to heat

water.
electromagnetic; thermal
mechanical; electromagnetic
solar; chemical
thermal; chemica
Physics
1 answer:
Naddik [55]3 years ago
4 0

Answer:

Electromagnetic; thermal

Explanation:

The energy of the sun is transferred directly to this type of panels, to produce water heating.

This type of panels are different from the photo voltaic, which convert solar energy to electric.

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A hand pushes two blocks, A and B, along a frictionless table for a distance d. When the hand starts to push, the blocks are mov
Kitty [74]
  <span>net work = change in kinetic energy 

for Block B, we just have the force from block A acting on it 
F(ab)d= .5(1)vf² - .5(1)(2²) 
F(ab)d= .5vf² - 2 

Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction 

10-F(ba)d = .5(4)vf² - .5(4)(2²) 
10-F(ba)d = 2vf² - 8 
F(ba)d = 18 - 2vf² 

now we have two equations: 
F(ba)d = 18 - 2vf² 
F(ab)d= .5vf² - 2 

since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab) 

10-.5vf² + 2 = 2vf² - 8 
12 - .5vf² = 2vf² - 8 
20 = 2.5vf² 
vf² = 8 

they both will have the same velocity 
KE of block A= .5(4)(2.828²) = 16 J 
KE of block B=.5(1)(2.828²) = 4 J</span>
5 0
4 years ago
What is the shortest possible time in which a bacterium could travel a distance of 8.4 cm across a petri dish at a constant spee
Dahasolnce [82]

speed of the bacterium is 3.5 mm/s

v = 3.5 mm/s

total distance traveled by bacterium = 8.4 cm

d = 8.4 cm = 84 mm

time take to cover the distance

t = \frac{d}{v}

t = \frac{84}{3.5} = 24 s

<em>so it will take 24 s to move this distance</em>

7 0
4 years ago
What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm?
mrs_skeptik [129]
The electrostatic force between two point charges is given by:
F=k_e  \frac{q_1 q_2}{r^2}
where
k_e = 8.99 \cdot 10^9 Nm^2 C^{-2} is the Coulomb's constant
q1 and q2 are the two charges
r is the distance between them

In our problem, charge 1 is
q_1 = +2 \muC = +2.0 \cdot 10^{-6}C
while charge 2 is
q_2 = -2 \mu C=-2.0 \cdot 10^{-6} C
and their distance is
r=5.0 cm=0.05 m

So, the electrostatic force between them is
F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(+2\cdot 10^{-6}C)(-2 \cdot 10^{-6}C)}{(0.05 m)^2} =-14.4 N

And the negative sign means the force is attractive, because the two charges have opposite sign.
7 0
3 years ago
Which is correct help asap
Wittaler [7]

Answer:

b

Explanation:

5 0
3 years ago
Jimmy is standing 300 feet away from a rocket that is being shot up into the air away from him at an angle of elevation of 70 de
ira [324]

Answer: Vertical height of rocket is 824.24ft

Explanation: see attachment.

Opp/ Adj = Tan 70°

h/ 300 = Tan 70°

h= 300tan 70°

h = 824.24ft

4 0
3 years ago
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