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BARSIC [14]
3 years ago
11

Guests = 320 portions of beets served = 8 oz. size of beet can = 40 oz. how many cans of beets required?

Mathematics
2 answers:
inessss [21]3 years ago
7 0

Answer:

Hence, 64 cans of beets are required.

Step-by-step explanation:

We are given:

Guests = 320

portions of beets served = 8 oz.

Total number of beets served=320×8= 2560 oz.

size of beet can = 40 oz.

Let 'n' be the total number of cans of beet required.

⇒  total number of beets served=n× size of beet can.

⇒ 2560=n×40

⇒ n=2560/40=64

Hence, the number of cans of beets  required=64 cans.


kumpel [21]3 years ago
4 0
Assuming each guest isn't a fatty and every guest eats only 1 portion

320 times 8oz=2560 oz needed

number of cans needed times oz per can=oz we need
n times 40=2560
divide both sides by 40
n=64

64 cans needed
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