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3 years ago

Guests = 320 portions of beets served = 8 oz. size of beet can = 40 oz. how many cans of beets required?

Mathematics

2 answers:

inessss [21]3 years ago

7 0

Answer:

Hence, 64 cans of beets are required.

Step-by-step explanation:

We are given:

Guests = 320

portions of beets served = 8 oz.

Total number of beets served=320×8= 2560 oz.

size of beet can = 40 oz.

Let 'n' be the total number of cans of beet required.

⇒ total number of beets served=n× size of beet can.

⇒ 2560=n×40

⇒ n=2560/40=64

Hence, the number of cans of beets required=64 cans.

kumpel [21]3 years ago

4 0

Assuming each guest isn't a fatty and every guest eats only 1 portion

320 times 8oz=2560 oz needed

number of cans needed times oz per can=oz we need
n times 40=2560
divide both sides by 40
n=64

64 cans needed

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4 years ago

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