Question

The human ear canal is about 2.3 cm long. If it is regarded as a tube open at one end and closed at the eardrum, what is the fundamental frequency around which we would expect hearing to be most sensitive?

Answer 1

Answer:

For the given conditions the fundamental frequency is 3728.26 Hertz

Explanation:

We know that for a pipe open at one end and closed at other end the fundamental frequency is given by

$f=\frac{V_{s}}{4L}$

where

f is the fundamental frequency

$V_{s}$ is the speed of sound in air in the surrounding conditions.

L = Length of the pipe

Applying values we get and using speed of sound as 343m/s we get

$f=\frac{343}{4\times 2.3\times 10^{-2}}=3728.26Hz$