A 76-kg ball is tied to one end of a massless string of length 1.3 m. The other end of the string is tied to a nail in the cente
r of a table. The ball is set into uniform circular motion around the nail, and the tension in the string is 51 N. How long does the ball take to make one complete revolution? Assume friction with the table is negligible.
2 answers:
You might be interested in
Answer:
101.54m/h
Explanation:
Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;
Let l be the be the distance further away at which they will meet from the current points;
#The speed toward each other.
Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h
Answer:
The energy of an electron in an isolated atom depends on b. n only.
Explanation:
The quantum number n, known as the principal quantum number represents the relative overall energy of each orbital.
The sets of orbitals with the same n value are often referred to as an electron shell, in an isolated atom all electrons in a subshell have exactly the same level of energy.
The principal quantum number comes from the solution of the Schrödinger wave equation, which describes energy in eigenstates , and for the case of an hydrogen atom we have:
Thus for each value of n we can describe the orbital and the energy corresponding to each electron on such orbital.
