A 76-kg ball is tied to one end of a massless string of length 1.3 m. The other end of the string is tied to a nail in the cente
r of a table. The ball is set into uniform circular motion around the nail, and the tension in the string is 51 N. How long does the ball take to make one complete revolution? Assume friction with the table is negligible.
2 answers:
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Answer:
<h3>0.445</h3>Explanation:
In friction, the coefficient of friction formula is expressed as;
Ff is the frictional force = Wsinθ
R is the reaction = Wcosθ
Substitute inti the equation;
Given
θ = 24°
Hence the coefficient of kinetic friction between the box and the ramp is 0.445
Answer:
8100W
Explanation:
Let g = 10m/s2
As water is falling from 60m high, its potential energy from 60m high would convert to power. So the rate of change in potential energy is
or 9000W
Since 10% of this is lost to friction, we take the remaining 90 %
P = 9000*90% = 8100 W