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3 years ago

"The gravity of the Sun causes the planets to move in a circular path."

1 answer:

3 0

You're thinking of Kepler's first law of planetary motion, but that's not
what it says.

First of all, Kepler didn't say anything about gravity. He only described
the orbits. And he said that the orbit of each planet is an <u>ellipse</u>, with the
sun at one focus.

If by some chance you're thinking of Newton ... he showed that <u>if</u> his formula for
gravity is correct, then the orbit of a planet <u>must</u> be an ellipse. But Newton's law
of gravity is not one of his so-called "three laws of motion".

You might be interested in

State the kinematic quantity that is equivalent to the slope of a position-time graph

Anni [7]

The figure shows the arrangement of given data.

The displacement is considered along X direction and time along Y direction.

The slope of the graph is given by tan θ

So tan θ = Δx/Δt = Velocity between those two points considered for finding slope of graph.

So slope of position time is graph is equivalent to kinematic quantity Velocity.

6 0

3 years ago

The model of the Adam has changed over time in light of new knowledge and discoveries. Which option correctly describes one such

katrin [286]

I think the correct answer from the choices listed above is option 3. The statement that correctly describe such change would be that about 1900 J.J. Thomas discovered electrons were negatively charged particles. Hope this answers the question. Have a nice day.

5 0

4 years ago

A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a

Zielflug [23.3K]

Answer: $F_{v} =\mu_{k} mg$

Magnitude of the force is 2601.9 N

Explanation:

m = 450 kg

coefficient of static friction μs = 0.73

coefficient of kinetic friction is μk = 0.59

The force required to start crate moving is $F_{s} =\mu_{s} mg$ .

but once crate starts moving the force of friction is reduced $F_{v} =\mu_{k} mg$ .

Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie $F_{v} =\mu_{k} mg$ .

Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.

Magnitude of the force

$F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9 N$

4 0

4 years ago

WILL MARK BRAINLIEST!!!!!!!

Deffense [45]

In a series circuit, all devices are constrained to a single flow of current. There can only be a single value for the current for all devices, otherwise this would violate the conservation of charge. Therefore the current must be the same across each resistor.

<h3>The answer is D.</h3>

7 0

4 years ago

Read 2 more answers

What force is needed to give a 4800.0 kg truck an acceleration of 6.2 m/s2 over a level road?

tekilochka [14]

Answer:

the force needed to give the truck the acceleration is 29,760 N.

Explanation:

Given;

mass of truck, m = 4800 kg

acceleration of the truck, a = 6.2 m/s²

The force needed to give the truck the acceleration is calculated as;

F = ma

F = 4800 x 6.2

F = 29,760 N

Therefore, the force needed to give the truck the acceleration is 29,760 N.

6 0

3 years ago