Ask question

Ask question

All categories

antoniya [11.8K]

3 years ago

12

Fuel is combusted in the _____ stroke of a four-stroke engine.

1 answer:

Margarita [4]3 years ago

3 0

Fuel is combusted in the <span>power </span>stroke of a four-stroke engine since this is where i<span>gnition of the fuel occurs and this stroke makes the substance gases to thrust in contact with the pistons.

</span>To add, the power stroke is the stage of the cycle of an internal combustion engine in which the piston is driven outward by the expansion of gases.

You might be interested in

Why do all freely falling objects have the same acceleration

iren2701 [21]

They are falling under the sole influence of gravity all objects<span> will </span>fall<span> with the </span>same<span> rate of </span><span>acceleration needless of there size</span>

8 0

3 years ago

Read 2 more answers

How to buy followers in insta <br><br> Because nothing <br> I just wanted to know

iren [92.7K]

No...........................................................................Work for them urself

7 0

3 years ago

Read 2 more answers

If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l

Ray Of Light [21]

Explanation:

The given data is as follows.

Concentration of caffeine = 2.97 mg/oz

Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

= $(12 \times 2.97)$ mg

= 35.64 mg

= $35.64 \times 10^{-3} g$

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

No. of cans = $\frac{\text{Lethal dose}}{\text{concentration in one can}}$

= $\frac{10 g}{35.64 \times 10^{-3} g}$

= 280.58

= 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0

3 years ago

Which of the following has been identified as one of the seven basic emotions that are present as early as infancy?

Irina-Kira [14]

The answer is c. interest.

4 0

3 years ago

What is the differential equation governing the growth of current in the circuit as a function of time after t=0? express the ri

Reika [66]

Answer:

$v_{b}=ir+L\frac{di}{dt}$

Explanation:

A differential equation that contain a term with di(t)/dt is in a RL circuit. Here we have

$v_{b}=v_{r}+v_{i}$

where vr is the voltage in the resistance, vi is the voltage in the inductance and vb is the source voltage. But also we have that

$v_{r}=ir\\v_{i}=L\frac{di}{dt}$

where L is the inductance of the circuit, r is the resistance an i is the current. By replacing we have the differential equation

$v_{b}=ir+L\frac{di}{dt}$

I hope this is useful for you

regards

3 0

3 years ago