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Anna007 [38]
3 years ago
13

Write the equation that links current, potential difference, and resistance

Physics
1 answer:
mrs_skeptik [129]3 years ago
4 0

You can write the equation in 3 different ways, depending on which quantity you want to be the dependent variable.  Any one of the three forms can be derived from either of the other two with a simple algebra operation.  They're all the same relationship, described by "Ohm's Law".

==> Current = (potential difference) / (resistance)

==> Potential difference = (current) x (resistance)

==> Resistance = (potential difference) / (resistance)

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During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 31.7 rad/s. Find the angular displ
Crank

Answer:

\Delta \theta = 3116.11\,rad and \Delta \theta = 495.944\,rev

Explanation:

The tub rotates at constant speed and the kinematic formula to describe the change in angular displacement (\Delta \theta), measured in radians, is:

\Delta \theta = \omega \cdot \Delta t

Where:

\omega - Steady angular speed, measured in radians per second.

\Delta t - Time, measured in seconds.

If \omega = 31.7\,\frac{rad}{s} and \Delta t = 98.3\,s, then:

\Delta \theta = \left(31.7\,\frac{rad}{s} \right)\cdot (98.3\,s)

\Delta \theta = 3116.11\,rad

The change in angular displacement, measured in revolutions, is given by the following expression:

\Delta \theta = (3116.11\,rad)\cdot \left(\frac{1}{2\pi} \frac{rev}{rad} \right)

\Delta \theta = 495.944\,rev

6 0
2 years ago
The different shapes of the moon seen from Earth are called
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Answer:

phases of moon

Explanation:

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3 0
2 years ago
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A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 5.0 km/h
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Answer

given,

time  = 10 s

ship's speed = 5 Km/h

F = m a

a is the acceleration and m is mass.

In the first case

F₁=m x a₁

where a₁ =  difference in velocity / time

F₁ is constant acceleration is also a constant.

Δv₁ = 5 x 0.278

Δv₁ = 1.39 m/s

a_1=\dfrac{1.39}{10}

a₁ = 0.139 m/s²

F₂ =m x a₂

F₃ = F₂ + F₁

Δv₃ = 19 x 0.278

Δv₃ = 5.282 m/s

a₃=Δv₂ / t

a_3=\dfrac{5.282}{10}

a₃ = 0.5282 m²/s

m a₃=m a₁ + m a₂

a₃ = a₂ + a₁

0.5282 = a₂ + 0.139

a₂=0.3892 m²/s

F₂ = m x 0.3892...........(1)

F₁ = m x 0.139...............(2)

F₂/F₁

ratio = \dfrac{0.3892}{0.139}

ratio = 2.8

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3 years ago
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