Answer:
Oxide of M is
and sulfate of 
Explanation:
0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.
Let moles of hydrogen gas be n.
Temperature of the gas ,T= 17°C =290 K
Pressure of the gas ,P= 741 mmHg= 0.9633 atm
Volume occupied by gas , V = 0.303 L
Using an ideal gas equation:


Moles of hydrogen gas produced = 0.01225 mol

Moles of metal =
So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

x = 2.9 ≈ 3


Formulas for the oxide and sulfate of M will be:
Oxide of M is
and sulfate of
.
Answer:
i think d maybe correct me if im wrong
Explanation:
Sodium reacts with fluorine to make a covalent bond between them. A covalent bond is formed when there is a mutual sharing of electrons between the two adjacent atoms.
Here, Sodium is metal and fluorine is non-metal. So, the bond between them may be an ionic bond, but as the Sodium has one valence electron and fluorine is highly electronegative. Sodium wants to lose electrons and fluorine wants to gain electrons to form a chemical bond. Therefore, the sodium donates its valence electron to fluorine, forms a cation, and fluorine accepts the electron and forms an anion and they distribute the difference in the charge between them.
So, we can say that when sodium and fluorine react to form sodium fluoride with a covalent bond.
Learn more about covalent bonds here:
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Answer:
Molecular formula = C₂H₄Cl₂
Explanation:
Molecular formula:
Molecular formula consist of symbols of elements present in compound with numbers of atoms of each element in subscript.
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number .
Given data:
Percentage of hydrogen = 4.07%
Percentage of Cl = 71.65%
Percentage of carbon = 24.27%
Molar mass = 99 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 4.07 / 1.01 = 4.0
Number of gram atoms of Cl = 71.65 / 35.5 = 2.0
Number of gram atoms of C = 24.27 / 12 = 2.0
Atomic ratio:
H : C : Cl
4/2 : 2/2 : 2/2
2 : 1 : 1
C : H : Cl = 1 : 2 : 1
Empirical formula is CH₂Cl.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 12+1×2+ 35.5 = 49.5
n = 99/49.5
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₂Cl)
Molecular formula = C₂H₄Cl₂
Preparation of small volumes of gases.