This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.
In this case, it is recommended to write the enthalpy for each substance as follows:

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and
and
are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

Finally we convert this result to kJ:

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For average speed, we divide the total distance covered by the total time taken.
After doing that, you will see that Jane has the lowest average speed.
Answer:
A
Explanation:
In all the other options either Carbon has more than 4 atoms attached or less than 4.
Carbon can not form more than four bonds. It can only share 4 electrons .
In other option C, No H-atom is linked in the right most Carbon.
whereas according to the definition of Hydrocarbon it should have been a Hydrogen atom.
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Answer:
The answer to your question is D