All categories

3 years ago

Give a theoretical reason why lithium and oxygen combine in the ratio 2:1

Chemistry

1 answer:

salantis [7]3 years ago

7 0

If a substance is made of pure element, Chances are they're gonna react with one another.

You might be interested in

A 50% antifreeze solution is to be mixed with a 90% antifreeze solution to get 200 liters of a 80% solution. How many liters of

sergey [27]

Answer:

50 ltr 150 ltr

Explanation:

this problem can be solved by the mixture and allegation concept which can be clearly understand from bellow figure in which the concentration of solution 1 is 50% and concentration of solution 2 is 90% before mixing after mixing with help bellow concept the ratio of concentration become 10:30

ratio of solution 1 and solution 2 =10:30

=1:3

total mixture is 200 liters

part of solution 1= $\frac{1}{4}$ ×200

=50 liters

part of solution 2= $\frac{3}{4}$ ×200

=150 liters

6 0

3 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

Have a nice day!

8 0

3 years ago

A reaction that occurs in the internal combustion engine is n2(g) + o2(g) ⇌ 2 no(g) (a) calculate δh o and δs o for the reaction

jekas [21]

1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.

7 0

3 years ago

For the reaction H₂O(g) + Cl₂O(g) → 2HClO(g), you know ΔS°rxn and S° of HClO(g) and of H₂O(g). Write an expression that can be u

expeople1 [14]

The expression for S°(Cl2O)(g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Given ,

The balanced chemical equation is ,

H2O (g) + Cl2O (g) → 2HClO (g)

The general standard entropy of the reaction is given by ,

ΔS°rxn = sum of the S°(Product ) - sum of the S°(reactants )

ΔS°rxn = ΣmS°products - ΣnS°reactants

where , m and n are the stoichiometry coefficients of each product and reactants .

Thus , the standard entropy of the given reaction is given by ,

ΔS°rxn = 2×S° (HClO)(g) - [ S°(H2O)(g) + S°(Cl2O)(g) ]

ΔS°rxn = 2×S° (HClO)(g) - S°(H2O)(g) - S°(Cl2O)(g)

Thus the S°(Cl2O) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Hence the expression for the standard entropy of Cl2O (g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

6 0

2 years ago

Alfredo is conducting an experiment on the effects of exercise on concentration. the independent variable is (the) ________ and

hodyreva [135]

1. exercise because you are using exercise to affect the amount of concentration. 2. concentration because concentration is what is being measured

4 0

4 years ago

Read 2 more answers