Answer:
See Below (Isolate the variables)
Step-by-step explanation:
13) d = 4AM solve for M
Divide both sides by 4A
14) = f+h solve for A
Multiply both sides by 6
A = 6( f+h)
15) h - m = qb solve for H
Add m to both sides
h - m = qb
+ m +m
h = qb + m
Answer:
The width of the frame is 0.0746 meters
Step-by-step explanation:
We are told that after the frame has been attached to the solar collector, the area that is left exposed is . As we see in the figure, the dimensions of this area are
and
where is the width of the frame.
The product of these dimensions must equal the exposed area:
Now since and
we have:
we expand this and solve for x using the quadratic formula:
we get two solutions:
We take the second solution i.e , because first one gives a width larger than the dimensions of the solar collector which cannot be possible.
Thus the width of the frame is 0.0746 meters.
