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Stella [2.4K]
3 years ago
14

Name 2 types of hydrocarbon that are produced in crackingAny ideas? Thank you

Chemistry
1 answer:
NeTakaya3 years ago
3 0
The answer is alkanes and alkenes
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What do you think happens to the bonds between atoms when substances melt?
Eduardwww [97]

Answer:

As a substance melts, and goes from a solid to a liquid state, the kinetic energy of the molecules increases, and the molecules move faster, and they separate further and further away from each other.  The intermolecluar forces holding the molecules together become weaker.  This is why a liquid can take fill the shape of its container, whereas a solid has a fixed shape.

Explanation:

take your notes man

6 0
3 years ago
What is the percent composition by mass of sulfur in the compound MgSO4 (gram formula mass = 120 g/mol)?
slavikrds [6]

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate. Explanation: Molar mass of compound = 120 g/mol.

7 0
2 years ago
ObIel WiLll unt COl.. USSMS A certain chemical reaction releases 31.2 kJ/g of heat for each gram of reactant consumed. How can y
aleksandr82 [10.1K]

Answer:

The expression to calculate the mass of the reactant is m = \frac{1.080kJ}{31.2kJ/g}

Explanation:

<em>The amount of heat released is equal to the amount of heat released per gram of reactant times the mass of the reactant.</em> To keep to coherence between units we need to transform 1,080 J to kJ. We do so with proportions:

1,080J.\frac{1kJ}{10^{3}J } =1.080kJ

Then,

1.080kJ=31.2\frac{kJ}{g} .m\\m = \frac{1.080kJ}{31.2kJ/g}

5 0
4 years ago
Read 2 more answers
Calculate the new volume of 1.23 mL of a gas at 32 C is subjected to drop in temperature of 20 degrees Celsius
kotykmax [81]

Answer:

1,15mL = V₂

Explanation:

Based on Charle's law the volume is directely proportional to the absolute temperature in a gas under constant pressure. The equation is:

V₁T₂ = V₂T₁

<em>Where V is volume and T absolute temperature of a gas where 1 is initial state and 2, final state.</em>

The V₁ is 1.23mL

T₁ = 32°C + 273.15 = 305.15K

T₂ = T₁ - 20°C = 285.15K

Replacing:

1.23mL*285.15K = V₂*305.15K

<h3>1,15mL = V₂</h3>

<em />

8 0
3 years ago
If I have an unknown quantity of gas at a pressure of 0.72 atm, a volume of 22
Darina [25.2K]

Answer:

0.64 mol

Explanation:

Using ideal gas equation as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question;

P = 0.72atm

V = 22 L

T = 30°C = 30 + 273 = 303K

n = ?

Using PV = nRT

n = PV/RT

n = (0.72 × 22) ÷ (0.0821 × 303)

n = 15.84 ÷ 24.88

n = 0.64 mol

8 0
3 years ago
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