If I have an unknown quantity of gas at a pressure of 0.72 atm, a volume of 22
1 answer:
Answer:
0.64 mol
Explanation:
Using ideal gas equation as follows;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information provided in this question;
P = 0.72atm
V = 22 L
T = 30°C = 30 + 273 = 303K
n = ?
Using PV = nRT
n = PV/RT
n = (0.72 × 22) ÷ (0.0821 × 303)
n = 15.84 ÷ 24.88
n = 0.64 mol
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