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2 years ago

What can you predict from an element's location on the periodic table?

Chemistry

1 answer:

Feliz [49]2 years ago

6 0

Answer:

properties

Explanation:

the location on the periodic table can indicate periodic trends such as electronegativity, ionization energy and also the proton amount of the element.

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Which one of the following statements is not true concerning 2.00 L of a 0.100 M solution of Ca3(PO4)2?

Len [333]

Answer: The correct answer is Option B.

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .......(1)

For A:

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

$0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{2.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 2.00L)=0.200mol$

Moles of calcium phosphate = 0.200 moles

For B:

1 mole of calcium phosphate contains 3 moles of calcium atoms, 2 moles of phosphate atoms and 8 moles of oxygen atoms.

So, 0.200 moles of calcium phosphate will contain = $(8\times 0.200)=1.6$ moles of oxygen atoms.

Moles of oxygen atoms = 1.6 moles

For C:

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 1.00 L

Putting values in equation 1, we get:

$0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{1.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 1.00L)=0.100mol$

Moles of calcium ions = $(0.100\times 3)=0.300$ moles

For D:

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 5.00 L

Putting values in equation 1, we get:

$0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{5.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 5.00L)=0.500mol$

Moles of phosphorus atoms = $(0.500\times 2)=1.00$ moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of atoms

Number of phosphorus atoms in 0.500 moles of calcium phosphate will be = $(1.00\times 6.022\times 10^{23})=6.022\times 10^{23}$

For E:

1 mole of calcium phosphate contains 3 moles of calcium ions and 2 moles of phosphate ions.

So, 0.200 moles of calcium phosphate will contain = $(3\times 0.200)=0.600$ moles of calcium ions

Moles of calcium ions = 0.600 moles

Hence, the correct answer is Option B.

6 0

2 years ago

Calculate the vapor pressure at 35ºC of a solution made by dissolving 20.2 g of sucrose (C12H22O11)in 60.5 g of water. The vapor

sukhopar [10]

Answer:

P' = 41.4 mmHg → Vapor pressure of solution

Explanation:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution (P')

Xm = Mole fraction for solute (Moles of solvent /Total moles)

Firstly we determine the mole fraction of solute.

Moles of solute → Mass . 1 mol / molar mass

20.2 g . 1 mol / 342 g = 0.0590 mol

Moles of solvent → Mass . 1mol / molar mass

60.5 g . 1 mol/ 18 g = 3.36 mol

Total moles = 3.36 mol + 0.0590 mol = 3.419 moles

Xm = 0.0590 mol / 3.419 moles → 0.0172

Let's replace the data in the formula

42.2 mmHg - P' = 42.2 mmHg . 0.0172

P' = - (42.2 mmHg . 0.0172 - 42.2 mmHg)

P' = 41.4 mmHg

5 0

3 years ago

What is a sentence for weathering

bija089 [108]

These rocks were either roasted or exposed to severe weathering

7 0

2 years ago

Read 2 more answers

) The cooling or warming of air that occurs because air is allowed to expand or is compressed, not because it is added or subtra

Pani-rosa [81]

Answer:

Adiabatic temperature changes.

Explanation:

Temperature changes related to changes of pressure without external gain or loss of heat. If no heat is added or lost to the surroundings, then when an air parcel rises and expands, its temperature drops. Conversely, when the parcel is compressed, its temperature rises. So the term adiabatic, implies a change in temperature of the air parcel without gain or loss of heat from outside the air parcel.

3 0

3 years ago

Consider the following expression:8.30 x 10^-5 = x(0.100 + x)^2We can solve for x using a technique called successive approximat

Black_prince [1.1K]

Answer:

a. x3 and x4 are the first to agree to two significant figures

b. x4 and x5 are the first to agree to three significant figures

Explanation:

8.30 x 10⁻⁵ = x1(0.100)²

8.30 x 10⁻⁵ = 0.01x1

x1 = 8.30 x 10⁻⁵/0.01 = 0.0083

8.30 x 10⁻⁵ = x2(0.100 + 0.0083)²

8.30 x 10⁻⁵ = (0.01172889)x2

x2 = 8.30 x 10⁻⁵/0.01172889

x2 = 0.007076543475128

8.30 x 10⁻⁵= x3 (0.100 + 0.007076543475128)²

8.30 x 10⁻⁵ = 0.011465386162581)x3

x3 = 8.30 x 10⁻⁵/0.011465386162581

x3 = 0.007239180505832

8.30 x 10⁻⁵ = x4 (0.100 + 0.007239180505832)²

8.30 x 10⁻⁵ = (0.011500241835562) x4

x4 = 8.30 x 10⁻⁵/0.011500241835562

x4 = 0.007217239531723

8.30 x 10⁻⁵ = x5 (0.1 + 0.007217239531723)²

8.30 x 10⁻⁵ = (0.011495536452803) x5

x5 = 8.30 x 10⁻⁵/0.011495536452803

x5 = 0.007220193710904

From the above results;

a. x3 and x4 are the first to agree to two significant figures

b. x4 and x5 are the first to agree to three significant figures

8 0

3 years ago