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3 years ago

True or false: the Molecules in a solid have MORE thermal energy than the molecules in a gas?

1 answer:

katrin2010 [14]3 years ago

3 0

That's false. Because, the molecules in a solid are compacted too tightly together that they don't have all that extra space that a gas would. Molecules in a gas would have more thermal energy because they have all that space to move around in. The more they move around, the hotter it gets. The less that they move around, and the more that they put and packed together, the colder it's going to be.

Hope this helped you!! (:

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A student found that the titration had taken 10.00 ml of 0.1002 m naoh to titration 0.132 g of aspirin, a monoprotic acid. calcu

Harman [31]

The balanced equation for the reaction between NaOH and aspirin is as follows;
NaOH + C₉H₈O₄ --> C₉H₇O₄Na + H₂O
stoichiometry of NaOH to C₉H₈O₄ is 1:1
The number of NaOH moles reacted - 0.1002 M / 1000 mL/L x 10.00 mL
Number of NaOH moles - 0.001002 mol
Therefore number of moles of aspirin - 0.001002 mol
Mass of aspirin reacted - 0.001002 mol x 180.2 g/mol = 0.18 g
However the mass of the aspirin sample is 0.132 g but 0.18 g of aspirin has reacted, therefore this question is not correct.

4 0

4 years ago

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Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t

Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

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4 years ago

How does the geosphere and biosphere interact

Vlada [557]

The geosphere, in turn, reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight (energy) from the atmosphere.

Explanation:

The geosphere, in return reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight energy from the atmosphere.
Scientists divide the planet into two the main components: the biosphere, which consists of all life.
The hydrosphere interacts with the geosphere when particles of water or rain cause land formations to erode.
biosphere is the part of the earth and its atmosphere capable of supporting life.
Geo sphere is the solid body of the earth.
Biosphere is the totality of living organisms and their environment.

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3 years ago

Distinguish between sugar and non-sugar with examples.

kap26 [50]

Answer:

Reducing sugars are sugars where the anomeric carbon has an OH group attached that can reduce other compounds. Non-reducing sugars do not have an OH group attached to the anomeric carbon so they cannot reduce other compounds. ... Maltose and lactose are reducing sugars, while sucrose is a non-reducing sugar

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3 years ago

What are the sources of petrochemicals

Sindrei [870]

Answer:

Petrochemicals are chemical products derived from petroleum, although many of the same chemical compounds are also obtained from other fossil fuels such as coal and natural gas or from renewable sources such as corn, sugar cane, and other types of biomass.

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3 years ago

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