The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.
The <em>first ionization energy</em> of hydrogen is 1312.0 kJ·mol⁻¹.
Thus, H atoms in the <em>n</em> = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when <em>n</em> = ∞.
According to Bohr, Eₙ = k/<em>n</em>².
If <em>n</em> = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.
If <em>n</em> = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹
∴ The ionization energy from <em>n</em> = 2 is 328 kJ·mol⁻¹
.
Answer: 2.7 centimeters long.
Explanation: count from starting at the beginning of the number on the ruler "2" and counted up until the end of the blue object. Counted 7 lines, so, 2.7 is the correct answer.
The number of electron or proton of an atom can change
depending on the chemical bond and the other chemical it is bonded with; an
atom can either gain or lose electron. However, the number of neutrons of an
atom can never change, this is the primary identity or signature of an atom.
Answer:
<span>neutrons</span>
Answer:
[OH⁻] = 10⁻¹⁴/[H⁺].
Explanation:
∵ [H⁺][OH⁻] = 10⁻¹⁴.
<em>∴ [OH⁻] = 10⁻¹⁴/[H⁺].</em>
